So I have a unit step function U(t)-U(t-1) and another function e^(-4t) *U(t). These functions are defined as vectors and vary from t_start to t_end. Now when I take the convolution of this function the resultant vector is almost twice the length of the time vector and hence I cannot use plot function to plot the convolved waveform. Any idea how to match the time axis and the convolution result so they can be plotted ? Thanks.
所以我有一个单位阶跃函数U（t）-U（t-1）和另一个函数e ^（ - 4t）* U（t）。这些函数被定义为向量，从t_start到t_end不等。现在，当我对该函数进行卷积时，合成矢量几乎是时间矢量长度的两倍，因此我无法使用绘图函数绘制卷积波形。知道如何匹配时间轴和卷积结果，以便绘制它们吗？谢谢。
1 个解决方案
#1
1
Use the 'same' argument to the conv function to get the same length out as you put in. Just make sure you give the arguments in the correct order.
使用conv函数的'same'参数可以获得与输入相同的长度。只需确保以正确的顺序给出参数。
#1
1
Use the 'same' argument to the conv function to get the same length out as you put in. Just make sure you give the arguments in the correct order.
使用conv函数的'same'参数可以获得与输入相同的长度。只需确保以正确的顺序给出参数。