Anyone know why this is happening:
有人知道为什么会这样:
Filename: 031\_Lobby.jpg
RegExp: (\d+)\_(.*)[^\_e|\_i]\.jpg
Replacement: \1\_\2\_i.jpg
That produces this:
生产:
031\_Lobb\_i.jpg
For some reason it's chopping the last character from the second back- reference (the "y" in "Lobby". It doesn't do that when I remove the [^_e|_i] so I must be doing something wrong that's related to that.
由于某种原因，它将最后一个字符从第二个引用(“大厅”中的“y”)中删除。没有,当我把[^ _e | _i]所以我一定是做错了什么相关的。
Thanks!
谢谢!
3 个解决方案
#1
4
You force it to chop off the last character with this part of your regex:
你强迫它用你的regex的这一部分砍掉最后一个字符:
[^_e|_i]
Which translates as: Any single character except "_", "e", "|", "i".
它的意思是:除了“_”、“e”、“|”、“i”之外的任何单个字符。
The "y" in "Lobby" matches this criterion.
“大厅”中的“y”符合这一标准。
You mean "not _e" and "not _i", obviously, but that's not the way to express it. This would be right:
你的意思显然是"not _e"和"not _i"，但那不是表达的方式。这将是正确的:
(\d+)_(.+)(?<!_[ei])\.jpg
Note that the dot needs to be escaped in regular expressions.
注意点需要在正则表达式中转义。
#2
1
it is removing the "y" because [^_e|_i] matches the y, and the .* matches everything before the y.
删除“y”是因为[^ _e | _i]匹配y,和之前的。*匹配一切y。
#3
-1
You're forcing it to have a last character different from _e and _i. You should use this instead (note the last *):
你强迫它有一个与_e和_i不同的最后一个字符。你应该使用这个(注意最后的*):
(\d+)_(.*)[^_e|_i]*.jpg
#1
4
You force it to chop off the last character with this part of your regex:
你强迫它用你的regex的这一部分砍掉最后一个字符:
[^_e|_i]
Which translates as: Any single character except "_", "e", "|", "i".
它的意思是:除了“_”、“e”、“|”、“i”之外的任何单个字符。
The "y" in "Lobby" matches this criterion.
“大厅”中的“y”符合这一标准。
You mean "not _e" and "not _i", obviously, but that's not the way to express it. This would be right:
你的意思显然是"not _e"和"not _i"，但那不是表达的方式。这将是正确的:
(\d+)_(.+)(?<!_[ei])\.jpg
Note that the dot needs to be escaped in regular expressions.
注意点需要在正则表达式中转义。
#2
1
it is removing the "y" because [^_e|_i] matches the y, and the .* matches everything before the y.
删除“y”是因为[^ _e | _i]匹配y,和之前的。*匹配一切y。
#3
-1
You're forcing it to have a last character different from _e and _i. You should use this instead (note the last *):
你强迫它有一个与_e和_i不同的最后一个字符。你应该使用这个(注意最后的*):
(\d+)_(.*)[^_e|_i]*.jpg