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As part of the RSpec, i need to reference a file contained in a gem I am depending on (call it gem foo). I control gem foo, so I can make changes to it as needed.

作为RSpec的一部分，我需要引用一个我依赖的gem中包含的文件（称之为gem foo）。我控制gem foo，所以我可以根据需要对它进行更改。

Gem 'foo' contains a file that I need to reference with in the a rspec spec. Is there a reasonably stable RubyGem or Bundler API to figure out 'foo' base directory?

Gem'foo'包含一个我需要在rspec规范中引用的文件。是否有一个相当稳定的RubyGem或Bundler API来找出'foo'基目录？

Assuming 'foo' is already required in my Gemfile: in Gemfile:

假设我的Gemfile中已经需要'foo'：在Gemfile中：

gem 'foo'

I want to do something like this (in something_spec.rb):

我想做这样的事情（在something_spec.rb中）：

filename = File.expand_path('examples/xml/result.xml', Gem.gem_base_path('foo'))

What is gem_base_path API call?

什么是gem_base_path API调用？

2 个解决方案

#1

I would recommend creating a function in your gem to do this:

我建议在gem中创建一个函数来执行此操作：

module Foo
  class Configuration
    def self.result_xml_path
      File.realpath("../examples/xml/result.xml")
    end
  end
end

You can then do the following in your spec:

然后，您可以在规范中执行以下操作：

filename = Foo::Configuration.result_xml_path

This is much safer since you are getting all the information from the gem. It also looks cleaner.

这样更安全，因为您从gem获取所有信息。它看起来也更清洁。

#2

This may do what you need without ant need to touch the 'foo' gem:

如果没有蚂蚁需要触摸'foo'宝石，这可能会做你需要的：

matches = Gem::Specification.find_all_by_name 'foo'
spec = matches.first
filename = File.expand_path('examples/xml/result.xml', spec.full_gem_path)

I have used this code to make something similar to what you need (namely loading in my specs some factories defined in a gem used by my project)

我已经使用这个代码来制作类似于你需要的东西（即在我的规范中加载我的项目使用的gem中定义的一些工厂）

#1