We have a single file in a fixed directory that will have the name database-x.x.x.zip where x.x.x is a version number that can change.
我们在固定目录中有一个文件名为database-x.x.x.zip,其中x.x.x是可以更改的版本号。
We want to create a batch script that will unzip this file - we can use 7zip to unzip the file from a batch script but we need to be able to pass the file name to 7zip - how can we determine the file name in a batch script given that the file name will not be constant?
我们想要创建一个将解压缩此文件的批处理脚本 - 我们可以使用7zip从批处理脚本解压缩文件,但我们需要能够将文件名传递给7zip - 我们如何在批处理脚本中确定文件名鉴于文件名不会是常数?
Update
Realized I should provide more details.. script needs to unzip an archive and then run an ant file which was in the archive:
实现我应该提供更多细节..脚本需要解压缩存档,然后运行存档中的ant文件:
"C:\Program Files\7-Zip\CommandLine\7za.exe" x %FILE%
ant -f %UNZIPPED_ARCHIVE_DIR%\db.xml
2 个解决方案
#1
0
use the fantastic for loop
使用梦幻般的循环
from the command line
从命令行
for /f "tokens=*" %f in ('dir database-?.?.?.?.zip /b') do 7za xxx %f
from the batch file
从批处理文件
for /f "tokens=*" %%f in ('dir database-?.?.?.?.zip /b') do 7za xxx %%f
where xxx is the options passes to 7zip
其中xxx是选项传递给7zip
#2
0
Source: extract.bat
:
@echo off
::: extract.bat - Extract all database-*.zip files in the given folder
::: usage: extract.bat [folder]
::: folder - Search for files here (defaults to current folder)
set search=database-*.zip /b
if "%~1" neq "" set search=%1\%search%
for /f "tokens=*" %%f in ('dir %search%') do (
7z x %%f %%~nf
ant -f %%~nf\db.xml
)
If you really need to exclude database zips that don't follow the version folder format (eg if there's one called database-old.zip
and that shouldn't be extracted) then you'll need to find a regex matcher for the command line in Windows - which is possible. That -or- if you keep your version numbers down to a single digit, then you can use the ?
single character match.
如果你真的需要排除不遵循版本文件夹格式的数据库拉链(例如,如果有一个名为database-old.zip并且不应该提取),那么你需要为命令行找到一个正则表达式匹配器在Windows中 - 这是可能的。那 - 或者 - 如果您将版本号保持为一位数,那么您可以使用?单个字符匹配。
You may also want to add some checking (before 7z...
line) to make sure he folder doesn't already exist and do something if it does.
您可能还想添加一些检查(在7z ...行之前)以确保他的文件夹不存在并执行某些操作。
#1
0
use the fantastic for loop
使用梦幻般的循环
from the command line
从命令行
for /f "tokens=*" %f in ('dir database-?.?.?.?.zip /b') do 7za xxx %f
from the batch file
从批处理文件
for /f "tokens=*" %%f in ('dir database-?.?.?.?.zip /b') do 7za xxx %%f
where xxx is the options passes to 7zip
其中xxx是选项传递给7zip
#2
0
Source: extract.bat
:
@echo off
::: extract.bat - Extract all database-*.zip files in the given folder
::: usage: extract.bat [folder]
::: folder - Search for files here (defaults to current folder)
set search=database-*.zip /b
if "%~1" neq "" set search=%1\%search%
for /f "tokens=*" %%f in ('dir %search%') do (
7z x %%f %%~nf
ant -f %%~nf\db.xml
)
If you really need to exclude database zips that don't follow the version folder format (eg if there's one called database-old.zip
and that shouldn't be extracted) then you'll need to find a regex matcher for the command line in Windows - which is possible. That -or- if you keep your version numbers down to a single digit, then you can use the ?
single character match.
如果你真的需要排除不遵循版本文件夹格式的数据库拉链(例如,如果有一个名为database-old.zip并且不应该提取),那么你需要为命令行找到一个正则表达式匹配器在Windows中 - 这是可能的。那 - 或者 - 如果您将版本号保持为一位数,那么您可以使用?单个字符匹配。
You may also want to add some checking (before 7z...
line) to make sure he folder doesn't already exist and do something if it does.
您可能还想添加一些检查(在7z ...行之前)以确保他的文件夹不存在并执行某些操作。