如何让Perl和Python打印正在执行的程序的每一行？

I know that bash -x script.sh will execute script printing each line before actual execution. How to make Perl and Python interpreters do the same?

我知道bash -x script.sh将在实际执行之前执行脚本打印每一行。如何使Perl和Python解释器做同样的事情？

3 个解决方案

#1

Devel::Trace is the Perl analogue, the trace module is Python's.

Devel :: Trace是Perl模拟，跟踪模块是Python的。

#2

Devel::DumpTrace was released in 2011 and has more features than Devel::Trace, such as evaluating variable values in the trace output.

Devel :: DumpTrace于2011年发布，具有比Devel :: Trace更多的功能，例如在跟踪输出中评估变量值。

#3

python -m trace -t main.py

python -m trace -t main.py

Test program:

测试程序：

main.py

main.py

from a import g
def f(i):
    g(i)
for i in range(3):
    f(i)

a.py

a.py

def g(i):
    print i

Output:

输出：

 --- modulename: main, funcname: <module>
main.py(1): from a import g
 --- modulename: a, funcname: <module>
a.py(1): def g(i):
main.py(2): def f(i):
main.py(4): for i in range(3):
main.py(5):     f(i)
 --- modulename: main, funcname: f
main.py(3):     g(i)
 --- modulename: a, funcname: g
a.py(2):     print i
0
main.py(4): for i in range(3):
main.py(5):     f(i)
 --- modulename: main, funcname: f
main.py(3):     g(i)
 --- modulename: a, funcname: g
a.py(2):     print i
1
main.py(4): for i in range(3):
main.py(5):     f(i)
 --- modulename: main, funcname: f
main.py(3):     g(i)
 --- modulename: a, funcname: g
a.py(2):     print i
2
main.py(4): for i in range(3):
 --- modulename: trace, funcname: _unsettrace
trace.py(80):         sys.settrace(None)

Tested on Ubuntu 16.10, Python 2.7.12.

在Ubuntu 16.10，Python 2.7.12上测试过。

#1