awk从atq检索第一个字段报告

I am learning awk to advance my skills and tried

我正在学习awk以提升我的技能并尝试过

$ atq | awk "{print $1}" 
28  Wed Oct 31 10:23:00 2018
27  Tue Oct 30 21:20:00 2018
25  Tue Oct 30 21:19:00 2018
29  Wed Oct 31 10:42:00 2018
26  Tue Oct 30 21:20:00 2018
20  Tue Oct 30 18:25:00 2018
30  Wed Oct 31 10:59:00 2018
32  Wed Oct 31 21:03:00 2018
23  Tue Oct 30 18:28:00 2018
31  Wed Oct 31 13:58:00 2018
19  Tue Oct 30 15:43:00 2018
21  Tue Oct 30 18:27:00 2018

It did not work as I expected, but it's relatively easy to work small programs together

它没有像我预期的那样工作,但是将小程序一起工作相对容易

$ atq | cut -f 1
28
27
25
29
26
20
30
32
23
31
19
21

How could I retrieve the first field using awk?

我怎么能用awk检索第一个字段?

1 个解决方案

#1

Try the below,

试试下面的,

atq | awk '{print $1}'

The single quotes stops the shell from expanding $1 to the shell's first positional parameter.

单引号阻止shell将$ 1扩展到shell的第一个位置参数。

#1