在Swift中使用模式运行shell命令

I would like to run a shell command on many files that should match on a given filename regex. I found this code snippet that runs a shell command with arguments:

我想在许多文件上运行shell命令，这些文件应该与给定的文件名正则表达式匹配。我发现这个代码片段运行带有参数的shell命令：

func shell(_ arguments: [String] = []) -> String {

    let task = Process()
    task.launchPath = "/usr/bin/env"
    task.arguments = arguments

    let pipe = Pipe()
    task.standardOutput = pipe
    task.launch()

    let data = pipe.fileHandleForReading.readDataToEndOfFile()
    let output = String(data: data, encoding: .utf8) ?? "unknown"

    return output
}

It runs great, but it does not resolve the parameters:

它运行良好，但它不解决参数：

shell(["ls", "~/Desktop/*.txt"])

Does not resolve the * to all txt files, it tries to only work on a file called *.txt. Is there some option I need to set on Process?

如果不解析*到所有txt文件，它会尝试仅处理名为* .txt的文件。我需要在Process上设置一些选项吗？

Thanks in advance for your help!

在此先感谢您的帮助！

1 个解决方案

#1

I just found out the answer! The resolving of * and other patterns is done by the shell, Process only runs a given command. So the solution is to create a shell and run the command in there: (will do some clean up in the code, but this works)

我刚刚找到了答案！ *和其他模式的解析由shell完成，Process只运行给定的命令。因此解决方案是创建一个shell并在那里运行命令:(将在代码中进行一些清理，但这可行）

shell(["bash", "-c", "ls ~/Desktop/*.txt"])