Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1
\
2
/
3
return [1,3,2]
.
Solution 1:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution
{
public:
vector<int> inorderTraversal(TreeNode* root)
{
if(root != NULL)
{
inorderTraversal(root->left);
v.push_back(root->val);
inorderTraversal(root->right);
}
return v;
}
private:
vector<int> v;
};
Solution 2: