I'm new in XSLT (v1.0) and I can't convert complex XHTML tables to LaTeX using XSLT.
我是XSLT (v1.0)的新手,不能使用XSLT将复杂的XHTML表转换为LaTeX。
What I mean when I said complex tables, are tables with rows with different number of columns. In other words, td
with colspan
.
当我说复杂表格时,我指的是列数不同的表格。换句话说,td与colspan。
i.e. (xhtml table)
例如(xhtml表)
<table border="1" cellspacing="0" cellpadding="0">
<tr>
<td valign="top" width="68" colspan="3"> <p>Values</p> </td>
</tr>
<tr>
<td valign="top" width="68"> <p>95</p> </td>
<td valign="top" width="68"> <p>169</p> <p> </p> </td>
<td valign="top" width="68"> <p>180</p> <p> </p> </td>
</tr>
</table>
What I'm doing in the XSL file is:
我在XSL文件中所做的是:
<xsl:template match="xhtml:table[@border='1']">
<xsl:text>\begin{center}</xsl:text>
<xsl:text>\begin{tabular}{</xsl:text>
<xsl:for-each select="xhtml:tr[1]/*">
<xsl:text>c</xsl:text>
<xsl:if test="position() = last()">
<xsl:text>} </xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:text>\toprule </xsl:text>
<xsl:for-each select="xhtml:tr">
<xsl:if test="position() != 1">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:if test="position() = 2">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:for-each select="xhtml:td|xhtml:th">
<xsl:if test="name() = 'th'">{\bf </xsl:if>
<xsl:apply-templates />
<xsl:if test="name() = 'th'">}</xsl:if>
<xsl:if test="position() != last()">
<xsl:text>&</xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:text> \\ </xsl:text>
</xsl:for-each>
<xsl:text>\bottomrule </xsl:text>
<xsl:text>\end{tabular} </xsl:text>
<xsl:text>\end{center} </xsl:text>
</xsl:template>
But as you can see, this code just works for simple tables, without the colspan attribute. The code loops around the first tr
, and for each td
, it writes an "c". So, in the case above, it will only create a one column table.
但是正如您所看到的,这段代码只适用于简单的表,没有colspan属性。代码围绕第一个tr循环,对于每个td,它都写一个“c”。因此,在上面的例子中,它只会创建一个列表。
What I want to do is count the number of td
, and the number of colspans if it exists, to create a correct table, with 3 columns.
我要做的是计算td的数量,如果存在的话,计算colspan的数量,以创建一个包含3列的正确表。
Does anyone knows how to do this? Thanks in advance.
有人知道怎么做吗?提前谢谢。
1 个解决方案
#1
6
This is easier in XSLT2 but you can use the (//*)[position() <= n]
idiom in XSLT 1 to iterate n times. I also fixed up your TeX a bit: \bf
has been deprecated since latex2e released in back in 1993:-)
在XSLT2中这更容易,但是您可以使用XSLT 1中的(/ *)[position() <= n]习语来迭代n次。我也修正了你的TeX:自1993年latex2e发布以来,\bf已经被弃用:-)
<table xmlns="http://www.w3.org/1999/xhtml"
border="1" cellspacing="0" cellpadding="0">
<tr>
<td valign="top" width="68" colspan="3"> <p>Values</p> </td>
</tr>
<tr>
<td valign="top" width="68"> <p>95</p> </td>
<td valign="top" width="68"> <p>169</p> <p> </p> </td>
<td valign="top" width="68"> <p>180</p> <p> </p> </td>
</tr>
</table>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xhtml="http://www.w3.org/1999/xhtml">
<xsl:output method="text"/>
<xsl:template match="xhtml:table[@border='1']">
<xsl:text>\begin{center} </xsl:text>
<xsl:text>\begin{tabular}{</xsl:text>
<xsl:for-each select="xhtml:tr[1]/*">
<xsl:choose>
<xsl:when test="@colspan">
<xsl:for-each select="(//*)[position()<=current()/@colspan]">c</xsl:for-each>
</xsl:when>
<xsl:otherwise>c</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
<xsl:text>} </xsl:text>
<xsl:text>\toprule </xsl:text>
<xsl:for-each select="xhtml:tr">
<xsl:if test="position() != 1">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:if test="position() = 2">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:for-each select="xhtml:td|xhtml:th">
<xsl:if test="self::xhtml:th">\bfseries </xsl:if>
<xsl:apply-templates />
<xsl:if test="position() != last()">
<xsl:text>&</xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:if test="position()!=last()"> \\ </xsl:if>
</xsl:for-each>
<xsl:text>\end{tabular} </xsl:text>
<xsl:text>\end{center}</xsl:text>
</xsl:template>
</xsl:stylesheet>
\begin{center}
\begin{tabular}{ccc}
\toprule
Values \\
\midrule
\midrule
95 & 169 & 180 \end{tabular}
\end{center}
#1
6
This is easier in XSLT2 but you can use the (//*)[position() <= n]
idiom in XSLT 1 to iterate n times. I also fixed up your TeX a bit: \bf
has been deprecated since latex2e released in back in 1993:-)
在XSLT2中这更容易,但是您可以使用XSLT 1中的(/ *)[position() <= n]习语来迭代n次。我也修正了你的TeX:自1993年latex2e发布以来,\bf已经被弃用:-)
<table xmlns="http://www.w3.org/1999/xhtml"
border="1" cellspacing="0" cellpadding="0">
<tr>
<td valign="top" width="68" colspan="3"> <p>Values</p> </td>
</tr>
<tr>
<td valign="top" width="68"> <p>95</p> </td>
<td valign="top" width="68"> <p>169</p> <p> </p> </td>
<td valign="top" width="68"> <p>180</p> <p> </p> </td>
</tr>
</table>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xhtml="http://www.w3.org/1999/xhtml">
<xsl:output method="text"/>
<xsl:template match="xhtml:table[@border='1']">
<xsl:text>\begin{center} </xsl:text>
<xsl:text>\begin{tabular}{</xsl:text>
<xsl:for-each select="xhtml:tr[1]/*">
<xsl:choose>
<xsl:when test="@colspan">
<xsl:for-each select="(//*)[position()<=current()/@colspan]">c</xsl:for-each>
</xsl:when>
<xsl:otherwise>c</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
<xsl:text>} </xsl:text>
<xsl:text>\toprule </xsl:text>
<xsl:for-each select="xhtml:tr">
<xsl:if test="position() != 1">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:if test="position() = 2">
<xsl:text>\midrule </xsl:text>
</xsl:if>
<xsl:for-each select="xhtml:td|xhtml:th">
<xsl:if test="self::xhtml:th">\bfseries </xsl:if>
<xsl:apply-templates />
<xsl:if test="position() != last()">
<xsl:text>&</xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:if test="position()!=last()"> \\ </xsl:if>
</xsl:for-each>
<xsl:text>\end{tabular} </xsl:text>
<xsl:text>\end{center}</xsl:text>
</xsl:template>
</xsl:stylesheet>
\begin{center}
\begin{tabular}{ccc}
\toprule
Values \\
\midrule
\midrule
95 & 169 & 180 \end{tabular}
\end{center}