I have observations on different families as given by variable folio
:
我对变量作品集给出的不同家庭有观察结果:
Folio
1. 10
2. 10
3. 30
4. 30
.
.
.
828. 7110
829. 7130
.
.
.
11841. 107570
11842. 107580
11843. 107590
However, as I have other databases with a different format, I need to add zeros to be able to have six digit codes for all observations so they look this way:
但是,由于我有其他数据库具有不同的格式,我需要添加零,以便能够为所有观察设置六位数代码,因此它们看起来像这样:
1. 000010
2. 000010
3. 000030
4. 000030
.
.
.
828. 007110
829. 007130
.
.
.
11841. 107570
11842. 107580
11843. 107590
Any advice?
2 个解决方案
#1
1
This works: Folio <- sprintf("%06d",Folio)
这有效:Folio < - sprintf(“%06d”,Folio)
#2
1
Using the awesome library stringr:
使用awesome库stringr:
library(stringr)
str_pad(folio, width = 6, side = c("left"), pad = "0")
#1
1
This works: Folio <- sprintf("%06d",Folio)
这有效:Folio < - sprintf(“%06d”,Folio)
#2
1
Using the awesome library stringr:
使用awesome库stringr:
library(stringr)
str_pad(folio, width = 6, side = c("left"), pad = "0")