I have the following scenario.
我有以下情况。
SOURCE TABLE 1
消息来源表1
CREATE TABLE #Table1
(
Div varchar(10),
Dept varchar(10),
States varchar(10)
)
INSERT INTO #Table1
SELECT 'Div1','Dept1','CA,NV,TX'
UNION ALL
SELECT 'Div2','Dept2','MI,OH,IN'
UNION ALL
SELECT 'Div3','Dept2','NY,NJ,PA'
UNION ALL
SELECT 'Div4','Dept1',NULL
SOURCE TABLE 2
消息来源表2
CREATE TABLE #Table2
(
Div varchar(10),
Dept varchar(10),
States varchar(10)
)
INSERT INTO #Table2
SELECT 'Div1','Dept1','CA'
UNION ALL
SELECT 'Div1','Dept1','NV, TX'
UNION ALL
SELECT 'Div1','Dept1','TX, CA'
UNION ALL
SELECT 'Div1','Dept1','CA, NV'
UNION ALL
SELECT 'Div2','Dept2','MI, OH'
UNION ALL
SELECT 'Div2','Dept2','MI, IN'
UNION ALL
SELECT 'Div2','Dept2','OH'
UNION ALL
SELECT 'Div3','Dept2','NY, NJ, PA'
DESIRED OUTPUT
CREATE TABLE #Table3
(
Div varchar(10),
Dept varchar(10),
States varchar(50)
)
INSERT INTO #Table3
SELECT 'Div1','Dept1','CA - (3), NV - (2), TX - (2)'
UNION ALL
SELECT 'Div2','Dept2','MI - (2), OH - (2), IN - (1)'
UNION ALL
SELECT 'Div3','Dept2','NY - (1), NJ - (1), PA - (1)'
UNION ALL
SELECT 'Div4','Dept1',NULL
SELECT * FROM #Table1
SELECT * FROM #Table2
SELECT * FROM #Table3
DROP TABLE #Table1
DROP TABLE #Table2
DROP TABLE #Table3
Goal: Based on #Table1
and #Table2
, join both table on Div
and Dept
fields and then aggregate the counts for distinct states in States
field and create an output where you have Div
, Dept
, and States
with unique count of each one of those states printed next to the state.
目标:基于#Table1和#Table2,在Div和Dept字段上加入两个表,然后在States字段中汇总不同状态的计数,并创建一个输出,其中包含Div,Dept和States,每个状态具有唯一计数印在国家旁边的州。
I am not sure how to achieve this. I am trying LIKE
but can't quite figure out how to make it dynamic. I will continue trying to see if I can figure out. Thought I would post this question here and see if I can get some assist.
我不知道如何实现这一目标。我正在尝试但却无法弄清楚如何让它变得动态。我会继续试着看看能不能搞清楚。以为我会在这里发布这个问题,看看能否得到一些帮助。
Thank you
UPDATE:
Desired Output
Div Dept States
Div1 Dept1 CA - (3), NV - (2), TX - (2)
Div2 Dept2 MI - (2), OH - (2), IN - (1)
Div3 Dept2 NY - (1), NJ - (1), PA - (1)
Div4 Dept1 NULL
3 个解决方案
#1
6
Your requirements are very nasty but as developers we have to work with what we've got. Here's a solution using Common Table Expression (CTE) extensively:
您的要求非常恶劣,但作为开发人员,我们必须使用我们所拥有的。这是一个广泛使用公用表表达式(CTE)的解决方案:
;WITH
CTE1 AS
(
SELECT Div, Dept,
REPLACE(States,' ','') + ',' AS States
FROM Table2
),
CTE2 AS
(
SELECT c1.Div, c1.Dept,
LEFT(c1.States,CHARINDEX(',', c1.States)-1) AS IndividualState,
RIGHT(c1.States,LEN(c1.States)-CHARINDEX(',', c1.States)) AS RemainingStates
FROM CTE1 c1
UNION ALL
SELECT c2.Div, c2.Dept,
LEFT(c2.RemainingStates,CHARINDEX(',', c2.RemainingStates)-1),
RIGHT(c2.RemainingStates,LEN(c2.RemainingStates) - CHARINDEX(',', c2.RemainingStates))
FROM CTE2 c2
WHERE LEN(c2.RemainingStates) > 0
),
CTE3 AS
(
SELECT Div, Dept,
IndividualState,
COUNT(*) AS StateCount
FROM CTE2
GROUP BY Div, Dept, IndividualState
),
CTE4 AS
(
SELECT t1.Div, t1.Dept,
(
SELECT c3.IndividualState + ' - (' + CONVERT(varchar(10),c3.StateCount) + '), '
FROM CTE3 c3
WHERE c3.Div = t1.Div AND c3.Dept = t1.Dept
FOR XML PATH('')
) AS States
FROM Table1 t1
)
SELECT Div, Dept,
LEFT(States, LEN(States) - 1) AS States
FROM CTE4
Explanation
-
CTE1
cleans up the data inTable2
: remove spaces, add a comma to the end -
CTE2
does the normalization -
CTE3
does the counting -
CTE4
does the final assembly, puttingCA | 3
intoCA - (3), ...
CTE1清理表2中的数据:删除空格,在末尾添加逗号
CTE2进行标准化
CTE3进行计数
CTE4进行最终组装,放入CA | 3进CA - (3),...
The last SELECT
remove the trailing comma for neater output.
最后一个SELECT删除neater输出的尾随逗号。
To better understand each step, you can replace the final SELECT
with SELECT * FROM CTE1
, SELECT * FROM CTE2
, etc.
为了更好地理解每个步骤,可以用SELECT * FROM CTE1,SELECT * FROM CTE2等替换最终的SELECT。
#2
6
Ok, so first of all, you'll need to split the concatenated values in #Temp1
and #Temp2
. There are various methods for doing so, I'll use the numbers table one that is described in this awesome blog post from Aaron Bertrand. So, we'll need a numbers table, which can be done this way:
好的,首先,您需要在#Temp1和#Temp2中拆分连接值。这样做有多种方法,我将使用Aaron Bertrand这篇精彩博客文章中描述的数字表。所以,我们需要一个数字表,可以这样做:
;WITH n AS
(
SELECT x = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
)
SELECT Number = x
INTO #Numbers
FROM n
WHERE x BETWEEN 1 AND 8000;
Then, you'll need to actually do the splitting and then a group concatenation method for your result:
然后,您需要实际执行拆分,然后为您的结果执行组连接方法:
;WITH T1 AS
(
SELECT *
FROM #Table1 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(',',T.States + ',', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(',' + T.States, Number, LEN(',')) = ',') N
), T2 AS
(
SELECT *
FROM #Table2 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(', ',T.States + ', ', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(', ' + T.States, Number, LEN(', ')) = ', ') N
), T3 AS
(
SELECT T1.Div, T1.Dept, T1.Item, COUNT(*) N
FROM T1
LEFT JOIN T2
ON T1.Div = T2.Div
AND T1.Dept = T2.Dept
AND T1.Item = T2.Item
GROUP BY T1.Div, T1.Dept, T1.Item
)
SELECT A.Div,
A.Dept,
States = STUFF((SELECT ',' + CONVERT(VARCHAR(20), Item) +
' - (' + CAST(N AS VARCHAR(4)) + ')'
FROM T3
WHERE Div = A.Div
AND Dept = A.Dept
FOR XML PATH(''), TYPE).value('.[1]','nvarchar(max)'),1,1,'')
FROM T3 A
ORDER BY Div, Dept, Item
The results are:
结果是:
╔══════╦═══════╦════════════════════════════╗
║ Div ║ Dept ║ States ║
╠══════╬═══════╬════════════════════════════╣
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div4 ║ Dept1 ║ NULL ║
╚══════╩═══════╩════════════════════════════╝
#3
2
Ideally of course this data would be normalized, because this is messy. Given that you're stuck with this structure, I think your best bet is to use a driver table of states or to use one of the many split functions available to split out the delimited values, and then use that, to get each state on it's own line:
理想情况下,这些数据当然会被标准化,因为这很麻烦。鉴于您坚持使用此结构,我认为您最好的选择是使用状态驱动程序表或使用可用的许多拆分函数之一来拆分分隔值,然后使用它来获取每个状态这是自己的路线:
;WITH cte AS (SELECT DISTINCT b.Div,b.Dept,a.abbrs
FROM #States a
RIGHT JOIN #Table1 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte2 AS (SELECT b.Div,b.Dept,a.abbrs
FROM #States a
JOIN #Table2 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte3 AS (SELECT a.Div,a.Dept,a.abbrs,CAST(COUNT(b.abbrs)AS VARCHAR(25)) CT
FROM cte a
LEFT JOIN cte2 b
ON a.Dept = b.Dept
AND a.Div = b.Div
AND a.abbrs = b.abbrs
GROUP BY a.div,a.dept,a.abbrs
)
SELECT DISTINCT
Div,Dept
,STUFF((SELECT DISTINCT ',' + abbrs+'-('+CT+')'
FROM cte3 b
WHERE a.Div = b.Div
AND a.Dept = b.Dept
FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
,1,1,'')
FROM cte3 a
Demo: SQL Fiddle
演示:SQL小提琴
Note:
- cte1 - creates distinct list of div/dept/state from table1
- cte2 - creates list of all div/dept/states from table2
- cte3 - aggregates on div/dept/state to get the count
cte1 - 从table1创建不同的div / dept / state列表
cte2 - 从table2创建所有div / dept / states的列表
cte3 - 在div / dept / state上聚合以获取计数
Output is:
| DIV | DEPT | STATES |
|------|-------|----------------------|
| Div1 | Dept1 | CA-(3),NV-(2),TX-(2) |
| Div2 | Dept2 | IN-(1),MI-(2),OH-(2) |
| Div3 | Dept2 | NJ-(1),NY-(1),PA-(1) |
| Div4 | Dept1 | (null) |
Updated fiddle to include your NULL
line and added output.
更新了小提琴以包含您的NULL行和添加的输出。
#1
6
Your requirements are very nasty but as developers we have to work with what we've got. Here's a solution using Common Table Expression (CTE) extensively:
您的要求非常恶劣,但作为开发人员,我们必须使用我们所拥有的。这是一个广泛使用公用表表达式(CTE)的解决方案:
;WITH
CTE1 AS
(
SELECT Div, Dept,
REPLACE(States,' ','') + ',' AS States
FROM Table2
),
CTE2 AS
(
SELECT c1.Div, c1.Dept,
LEFT(c1.States,CHARINDEX(',', c1.States)-1) AS IndividualState,
RIGHT(c1.States,LEN(c1.States)-CHARINDEX(',', c1.States)) AS RemainingStates
FROM CTE1 c1
UNION ALL
SELECT c2.Div, c2.Dept,
LEFT(c2.RemainingStates,CHARINDEX(',', c2.RemainingStates)-1),
RIGHT(c2.RemainingStates,LEN(c2.RemainingStates) - CHARINDEX(',', c2.RemainingStates))
FROM CTE2 c2
WHERE LEN(c2.RemainingStates) > 0
),
CTE3 AS
(
SELECT Div, Dept,
IndividualState,
COUNT(*) AS StateCount
FROM CTE2
GROUP BY Div, Dept, IndividualState
),
CTE4 AS
(
SELECT t1.Div, t1.Dept,
(
SELECT c3.IndividualState + ' - (' + CONVERT(varchar(10),c3.StateCount) + '), '
FROM CTE3 c3
WHERE c3.Div = t1.Div AND c3.Dept = t1.Dept
FOR XML PATH('')
) AS States
FROM Table1 t1
)
SELECT Div, Dept,
LEFT(States, LEN(States) - 1) AS States
FROM CTE4
Explanation
-
CTE1
cleans up the data inTable2
: remove spaces, add a comma to the end -
CTE2
does the normalization -
CTE3
does the counting -
CTE4
does the final assembly, puttingCA | 3
intoCA - (3), ...
CTE1清理表2中的数据:删除空格,在末尾添加逗号
CTE2进行标准化
CTE3进行计数
CTE4进行最终组装,放入CA | 3进CA - (3),...
The last SELECT
remove the trailing comma for neater output.
最后一个SELECT删除neater输出的尾随逗号。
To better understand each step, you can replace the final SELECT
with SELECT * FROM CTE1
, SELECT * FROM CTE2
, etc.
为了更好地理解每个步骤,可以用SELECT * FROM CTE1,SELECT * FROM CTE2等替换最终的SELECT。
#2
6
Ok, so first of all, you'll need to split the concatenated values in #Temp1
and #Temp2
. There are various methods for doing so, I'll use the numbers table one that is described in this awesome blog post from Aaron Bertrand. So, we'll need a numbers table, which can be done this way:
好的,首先,您需要在#Temp1和#Temp2中拆分连接值。这样做有多种方法,我将使用Aaron Bertrand这篇精彩博客文章中描述的数字表。所以,我们需要一个数字表,可以这样做:
;WITH n AS
(
SELECT x = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
)
SELECT Number = x
INTO #Numbers
FROM n
WHERE x BETWEEN 1 AND 8000;
Then, you'll need to actually do the splitting and then a group concatenation method for your result:
然后,您需要实际执行拆分,然后为您的结果执行组连接方法:
;WITH T1 AS
(
SELECT *
FROM #Table1 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(',',T.States + ',', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(',' + T.States, Number, LEN(',')) = ',') N
), T2 AS
(
SELECT *
FROM #Table2 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(', ',T.States + ', ', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(', ' + T.States, Number, LEN(', ')) = ', ') N
), T3 AS
(
SELECT T1.Div, T1.Dept, T1.Item, COUNT(*) N
FROM T1
LEFT JOIN T2
ON T1.Div = T2.Div
AND T1.Dept = T2.Dept
AND T1.Item = T2.Item
GROUP BY T1.Div, T1.Dept, T1.Item
)
SELECT A.Div,
A.Dept,
States = STUFF((SELECT ',' + CONVERT(VARCHAR(20), Item) +
' - (' + CAST(N AS VARCHAR(4)) + ')'
FROM T3
WHERE Div = A.Div
AND Dept = A.Dept
FOR XML PATH(''), TYPE).value('.[1]','nvarchar(max)'),1,1,'')
FROM T3 A
ORDER BY Div, Dept, Item
The results are:
结果是:
╔══════╦═══════╦════════════════════════════╗
║ Div ║ Dept ║ States ║
╠══════╬═══════╬════════════════════════════╣
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div4 ║ Dept1 ║ NULL ║
╚══════╩═══════╩════════════════════════════╝
#3
2
Ideally of course this data would be normalized, because this is messy. Given that you're stuck with this structure, I think your best bet is to use a driver table of states or to use one of the many split functions available to split out the delimited values, and then use that, to get each state on it's own line:
理想情况下,这些数据当然会被标准化,因为这很麻烦。鉴于您坚持使用此结构,我认为您最好的选择是使用状态驱动程序表或使用可用的许多拆分函数之一来拆分分隔值,然后使用它来获取每个状态这是自己的路线:
;WITH cte AS (SELECT DISTINCT b.Div,b.Dept,a.abbrs
FROM #States a
RIGHT JOIN #Table1 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte2 AS (SELECT b.Div,b.Dept,a.abbrs
FROM #States a
JOIN #Table2 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte3 AS (SELECT a.Div,a.Dept,a.abbrs,CAST(COUNT(b.abbrs)AS VARCHAR(25)) CT
FROM cte a
LEFT JOIN cte2 b
ON a.Dept = b.Dept
AND a.Div = b.Div
AND a.abbrs = b.abbrs
GROUP BY a.div,a.dept,a.abbrs
)
SELECT DISTINCT
Div,Dept
,STUFF((SELECT DISTINCT ',' + abbrs+'-('+CT+')'
FROM cte3 b
WHERE a.Div = b.Div
AND a.Dept = b.Dept
FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
,1,1,'')
FROM cte3 a
Demo: SQL Fiddle
演示:SQL小提琴
Note:
- cte1 - creates distinct list of div/dept/state from table1
- cte2 - creates list of all div/dept/states from table2
- cte3 - aggregates on div/dept/state to get the count
cte1 - 从table1创建不同的div / dept / state列表
cte2 - 从table2创建所有div / dept / states的列表
cte3 - 在div / dept / state上聚合以获取计数
Output is:
| DIV | DEPT | STATES |
|------|-------|----------------------|
| Div1 | Dept1 | CA-(3),NV-(2),TX-(2) |
| Div2 | Dept2 | IN-(1),MI-(2),OH-(2) |
| Div3 | Dept2 | NJ-(1),NY-(1),PA-(1) |
| Div4 | Dept1 | (null) |
Updated fiddle to include your NULL
line and added output.
更新了小提琴以包含您的NULL行和添加的输出。