交叉线程操作无效[重复]

Possible Duplicate:
Cross-thread operation not valid: Control accessed from a thread other than the thread it was created on

可能的重复:交叉线程操作无效:从线程以外的线程访问控制。

Okay, I know why this is giving me this error:

好的，我知道为什么会有这样的错误

Cross-thread operation not valid: Control 'Form1' accessed from a thread other than the thread it was created on.

跨线程操作无效:控制“Form1”从线程以外的线程访问。

But... How can I make this workable?

但是…我怎样才能使它可行呢?

System.Threading.Thread t = new System.Threading.Thread(()=>
{
   // do really hard work and then...
   listView1.Items.Add(lots of items);
   lots more UI work
});
t.Start();

I don't care when, or how the Thread finishes, so I don't really care about anything fancy or over complicated atm, unless it'll make things much easier when working with the UI in a new Thread.

我不关心线程何时结束，也不关心线程如何结束，所以我不关心任何花哨的东西，也不关心复杂的atm，除非在新的线程中使用UI会使事情变得更容易。

2 个解决方案

#1

You can't. UI operations must be performed on the owning thread. Period.

你不能。UI操作必须在拥有的线程上执行。时期。

What you could do, is create all those items on a child thread, then call Control.Invoke and do your databinding there.

您可以做的是，在子线程上创建所有这些项，然后调用Control。在那里调用并执行数据库。

Or use a BackgroundWorker

或者使用BackgroundWorker

    BackgroundWorker bw = new BackgroundWorker();
    bw.DoWork += (s, e) => { /* create items */ };
    bw.RunWorkerCompleted += (s, e) => { /* databind UI element*/ };

    bw.RunWorkerAsync();

#2

When you access the from's property from another thread, this exception is thrown. To work around this problem there's at least 2 options.

当您从另一个线程访问from的属性时，将抛出此异常。要解决这个问题，至少有两个选择。

Telling Control to don't throw these exceptions (which is not recommended):

告诉控件不要抛出这些异常(不建议抛出):

Control.CheckForIllegalCrossThreadCalls = false;

控制。CheckForIllegalCrossThreadCalls = false;

Using threadsafe functions:

使用线程安全的功能:

private void ThreadSafeFunction(int intVal, bool boolVal)
{
    if (this.InvokeRequired)
    {
        this.Invoke(
            new MethodInvoker(
            delegate() { ThreadSafeFunction(intVal, boolVal); }));
    }
    else
    {
        //use intval and boolval
    }
}

#1