I've seen other related questions but not quite like mine.
我见过其他相关的问题,但不太像我的。
I have blocks of code with varying number of rows and want to group those rows, including the "last" div:
我有不同行数的代码块,并希望对这些行进行分组,包括“last”div:
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
I want:
我想要:
<div class="wrapper">
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
</div>
<br>
<div class="wrapper">
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
</div>
<br>
<div class="wrapper">
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
</div>
I've tried various find, addBefore, wrapAll variations but just can't get it.
我尝试了各种find,addBefore,wrapAll变种但却无法得到它。
I've tried variations of:
我尝试过各种变化:
$(this).find(".row, .last").wrapAll('<div class="wrapper"></div>');
2 个解决方案
#1
1
We can acheive this by combining prevAll and wrapAll. Below is the ocde
我们可以通过组合prevAll和wrapAll来实现这一点。下面是ocde
$("div.last").each(function() {
$(this).prevAll(".row").addBack().wrapAll("<div class='wrapper' />");
});
Demo : https://jsfiddle.net/wx8074qn/3/
演示:https://jsfiddle.net/wx8074qn/3/
#2
3
Here is one way:-
这是一种方式: -
//find all the 'first' .row by checking the previous is not a .row
$('.row').prev(':not(.row)').next().each(function() {
//wrap all next elements until you find something not a div
$(this).nextUntil(':not(div)').addBack().wrapAll($("<div></div>", {
class: 'wrapper'
}));
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
#1
1
We can acheive this by combining prevAll and wrapAll. Below is the ocde
我们可以通过组合prevAll和wrapAll来实现这一点。下面是ocde
$("div.last").each(function() {
$(this).prevAll(".row").addBack().wrapAll("<div class='wrapper' />");
});
Demo : https://jsfiddle.net/wx8074qn/3/
演示:https://jsfiddle.net/wx8074qn/3/
#2
3
Here is one way:-
这是一种方式: -
//find all the 'first' .row by checking the previous is not a .row
$('.row').prev(':not(.row)').next().each(function() {
//wrap all next elements until you find something not a div
$(this).nextUntil(':not(div)').addBack().wrapAll($("<div></div>", {
class: 'wrapper'
}));
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>
<br>
<div class="row"></div>
<div class="row"></div>
<div class="row"></div>
<div class="last"></div>