C ++“cin”只读取第一个单词[复制]

This question already has an answer here:

这个问题在这里已有答案:

std::cin.getline( ) vs. std::cin 3 answers

std :: cin.getline()vs。std :: cin 3 answers

#include<iostream.h>
#include<conio.h>
class String
{
    char str[100];
    public:
    void input()
    {
        cout<<"Enter string :";
        cin>>str;
    }

    void display()
    {
        cout<<str;
    }
};

int main()
{
     String s;
     s.input();
     s.display();
     return 0;
}

I am working in Turbo C++ 4.5. The code is running fine but its not giving the desired output for e.g if i give input as "steve hawking" only "steve" is being displayed. Can anyone please help?

我在Turbo C ++ 4.5中工作。代码运行正常,但它没有给出所需的输出,例如,如果我输入“steve hawking”只显示“史蒂夫”。有人可以帮忙吗?

5 个解决方案

#1

Using >> on a stream reads one word at a time. To read a whole line into a char array:

在流上使用>>一次读取一个单词。要将整行读入char数组:

cin.getline(str, sizeof str);

Of course, once you've learnt how to implement a string, you should use std::string and read it as

当然,一旦你学会了如何实现一个字符串,你应该使用std :: string并将其读作

getline(cin, str);

It would also be a very good idea to get a compiler from this century; yours is over 15 years old, and C++ has changed significantly since then. Visual Studio Express is a good choice if you want a free compiler for Windows; other compilers are available.

从本世纪开始编译器也是一个非常好的主意;你的年龄超过15岁,从那时起C ++发生了重大变化。如果您想要一个免费的Windows编译器,Visual Studio Express是一个不错的选择;其他编译器可用。

#2

cin>>str;

This only reads in the next token. In C++ iostreams, tokens are separated by whitespace, so you get the first word.

这只会读入下一个标记。在C ++ iostreams中,令牌由空格分隔,因此您获得第一个单词。

You probably want getline, which reads an entire line into a string:

你可能想要getline,它将整行读入一个字符串:

getline(cin, str);

#3

You can use :

您可以使用 :

   cin.read( str, sizeof(str) );

But, this will fill up the buffer. Instead you should use cin.getLine() as MikeSeymour suggested

但是,这将填补缓冲区。相反,你应该使用cin.getLine()作为MikeSeymour建议

#4

You could use cin.getline to read the whole line.

您可以使用cin.getline来读取整行。

#5

use this

cin.getline(cin, str);

#1