从电话号码中删除dash

What regular expression using java could be used to filter out dashes '-' and open close round brackets from a string representing phone numbers...

使用java的正则表达式可以用来过滤掉dashes的“-”，并从代表电话号码的字符串中打开封闭的括号。

so that (234) 887-9999 should give 2348879999 and similarly 234-887-9999 should give 2348879999.

所以(234)887-9999应该是2348879999，类似的234-887-9999应该是2348879999。

Thanks,

谢谢,

2 个解决方案

#1

phoneNumber.replaceAll("[\\s\\-()]", "");

The regular expression defines a character class consisting of any whitespace character (\s, which is escaped as \\s because we're passing in a String), a dash (escaped because a dash means something special in the context of character classes), and parentheses.

正则表达式定义了一个由任何空格字符组成的字符类(\s，它被转义成\s，因为我们传入了一个字符串)、一个破折号(转义是因为破折号在字符类上下文中是特殊的)和圆括号。

See String.replaceAll(String, String).

看到字符串。replaceAll(字符串,字符串)。

EDIT

编辑

Per gunslinger47:

每gunslinger47:

phoneNumber.replaceAll("\\D", "");

Replaces any non-digit with an empty string.

用空字符串替换任何非数字。

#2

    public static String getMeMyNumber(String number, String countryCode)
    {    
         String out = number.replaceAll("[^0-9\\+]", "")        //remove all the non numbers (brackets dashes spaces etc.) except the + signs
                        .replaceAll("(^[1-9].+)", countryCode+"$1")         //if the number is starting with no zero and +, its a local number. prepend cc
                        .replaceAll("(.)(\\++)(.)", "$1$3")         //if there are left out +'s in the middle by mistake, remove them
                        .replaceAll("(^0{2}|^\\+)(.+)", "$2")       //make 00XXX... numbers and +XXXXX.. numbers into XXXX...
                        .replaceAll("^0([1-9])", countryCode+"$1");         //make 0XXXXXXX numbers into CCXXXXXXXX numbers
         return out;

    }

#1

phoneNumber.replaceAll("[\\s\\-()]", "");