I have the following data frame and i want to use cast to create a "pivot table" with columns for two values (value and percent). Here is the data frame:
我有下面的数据框架，我想使用cast创建一个包含两个值(值和百分比)的列的“pivot表”。这是数据框架:
expensesByMonth <- structure(list(month = c("2012-02-01", "2012-02-01", "2012-02-01",
"2012-02-01", "2012-02-01", "2012-02-01", "2012-02-01", "2012-02-01",
"2012-02-01", "2012-02-01", "2012-02-01", "2012-02-01", "2012-03-01",
"2012-03-01", "2012-03-01", "2012-03-01", "2012-03-01", "2012-03-01",
"2012-03-01", "2012-03-01", "2012-03-01", "2012-03-01", "2012-03-01",
"2012-03-01", "2012-03-01", "2012-03-01", "2012-03-01", "2012-04-01",
"2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01",
"2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01",
"2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01", "2012-04-01",
"2012-04-01", "2012-04-01", "2012-05-01", "2012-05-01", "2012-05-01",
"2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01",
"2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01",
"2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01", "2012-05-01",
"2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01",
"2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01",
"2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01",
"2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01", "2012-06-01",
"2012-07-01", "2012-07-01", "2012-07-01", "2012-07-01", "2012-07-01",
"2012-07-01", "2012-07-01", "2012-07-01", "2012-07-01", "2012-07-01",
"2012-07-01", "2012-07-01", "2012-07-01"),
expense_type = c("Adjustment", "Bank Service Charge", "Cable", "Clubbing", "Dining", "Education",
"Gifts", "Groceries", "Lunch", "Personal Care", "Rent", "Transportation",
"Adjustment", "Bank Service Charge", "Cable", "Clubbing", "Dining",
"Gifts", "Groceries", "Lunch", "Medical Expenses", "Miscellaneous",
"Personal Care", "Phone", "Recreation", "Rent", "Transportation",
"Adjustment", "Bank Service Charge", "Clothes", "Clubbing", "Computer",
"Dining", "Gifts", "Groceries", "Lunch", "Maintenance", "Medical Expenses",
"Miscellaneous", "Personal Care", "Phone", "Recreation", "Rent",
"Transportation", "Travel", "Bank Service Charge", "Cable", "Clothes",
"Clubbing", "Computer", "Dining", "Electric", "Gifts", "Groceries",
"Lunch", "Maintenance", "Medical Expenses", "Miscellaneous",
"Personal Care", "Phone", "Recreation", "Rent", "Transportation",
"Adjustment", "Bank Service Charge", "Cable", "Charity", "Clothes",
"Computer", "Dining", "Education", "Electric", "Gifts", "Groceries",
"Lunch", "Maintenance", "Medical Expenses", "Miscellaneous",
"Personal Care", "Phone", "Recreation", "Rent", "Transportation",
"Computer", "Gifts", "Groceries", "Lunch", "Maintenance", "Medical Expenses",
"Miscellaneous", "Personal Care", "Phone", "Recreation", "Rent",
"Repair and Maintenance", "Transportation"),
value = c(442.37, 200, 21.33, 75, 22.5, 1800, 10, 233.33, 154.75, 30, 545, 32.5,
2, 200, 36.33, 206.55, 74.5, 89, 372.68, 383.75, 144.19, 508.11,
30, 38.4, 81.75, 1746.7, 35, 16.37, 200, 806.9, 324.81, 756,
80.5, 100, 398.37, 326.25, 151, 29.95, 101, 90, 38.45, 61, 743.75,
129, 228.53, 200, 39.05, 237, 40, 283.83, 141.32, 32.88, 30,
424.4, 412, 142.75, 86.55, 1051.5, 30, 38.9, 51.5, 749.7, 35,
10, 200, 16, 32.59, 149.81, 100, 80, 60, 31.91, 55, 397.25, 486.4,
115.6, 47.08, 1000, 120, 41.11, 256, 761.6, 55, 10.54, 10, 342.11,
291, 76.5, 66.8, 1008, 30, 41.11, 316, 765, 65, 62),
percent = c(0.124025030980324, 0.0560729845967511, 0.00598018380724351, 0.0210273692237817,
0.0063082107671345, 0.50465686137076, 0.00280364922983756, 0.0654175474797997,
0.0433864718317362, 0.00841094768951267, 0.152798883026147, 0.00911185999697206,
0.000506462461002391, 0.0506462461002391, 0.00919989060410842,
0.0523049106600219, 0.018865726672339, 0.0225375795146064, 0.0943742149831854,
0.0971774847048337, 0.0365134111259673, 0.128669320529962, 0.00759693691503586,
0.0097240792512459, 0.0207016530934727, 0.442318990316438, 0.00886309306754183,
0.00357276925628781, 0.0436502047194601, 0.176106750940662, 0.0708901149746392,
0.164997773839559, 0.0175692073995827, 0.0218251023597301, 0.0869446602704567,
0.0712043964486193, 0.0329559045631924, 0.00653661815673915,
0.0220433533833274, 0.0196425921237571, 0.00839175185731621,
0.0133133124394353, 0.162324198800492, 0.0281543820440518, 0.0498769064226911,
0.0496724104530621, 0.00969853814096037, 0.0588618063868785,
0.00993448209061241, 0.070492601294463, 0.0350985252261336, 0.0081661442784834,
0.00745086156795931, 0.105404854981398, 0.102325165533308, 0.035453682960873,
0.0214957356235626, 0.261152697956974, 0.00745086156795931, 0.00966128383312057,
0.0127906456916635, 0.186197030583303, 0.00869267182928586, 0.00249044292527426,
0.0498088585054852, 0.00398470868043882, 0.00811635349346881,
0.0373093254635337, 0.0249044292527426, 0.0199235434021941, 0.0149426575516456,
0.00794700337455016, 0.0136974360890084, 0.09893284520652, 0.12113514388534,
0.0287895202161704, 0.0117250052921912, 0.249044292527426, 0.0298853151032911,
0.0102382108658025, 0.0637553388870211, 0.189672133188888, 0.0136974360890084,
0.00341757293956667, 0.0032424790697976, 0.110928451456846, 0.0943561409311103,
0.0248049648839517, 0.021659760186248, 0.326841890235599, 0.00972743720939281,
0.013329831455938, 0.102462338605604, 0.248049648839517, 0.0210761139536844,
0.0201033702327451)),
.Names = c("month", "expense_type", "value", "percent"),
row.names = c(NA, -96L),
class = "data.frame"
)
This is what i would like to create (of course, with different header names like: [month]_value, [month]_percent):
这就是我想创建的(当然，有不同的标题名，如:[月]_value，[月]_percent):
expenses value percent value.1 percent.1 value.2 percent.2 value.3 percent.3 value.4 percent.4 value.5 percent.5
1 Adjustment 442.37 0.124025031 2.00 0.000506462 16.37 0.003572769 0.00 0.000000000 10.00 0.002490443 0.00 0.000000000
2 Bank Service Charge 200.00 0.056072985 200.00 0.050646246 200.00 0.043650205 200.00 0.049672410 200.00 0.049808859 0.00 0.000000000
3 Cable 21.33 0.005980184 36.33 0.009199891 0.00 0.000000000 39.05 0.009698538 16.00 0.003984709 0.00 0.000000000
4 Charity 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 32.59 0.008116353 0.00 0.000000000
5 Clothes 0.00 0.000000000 0.00 0.000000000 806.90 0.176106751 237.00 0.058861806 149.81 0.037309325 0.00 0.000000000
6 Clubbing 75.00 0.021027369 206.55 0.052304911 324.81 0.070890115 40.00 0.009934482 0.00 0.000000000 0.00 0.000000000
7 Computer 0.00 0.000000000 0.00 0.000000000 756.00 0.164997774 283.83 0.070492601 100.00 0.024904429 10.54 0.003417573
8 Dining 22.50 0.006308211 74.50 0.018865727 80.50 0.017569207 141.32 0.035098525 80.00 0.019923543 0.00 0.000000000
9 Education 1800.00 0.504656861 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 60.00 0.014942658 0.00 0.000000000
10 Electric 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 32.88 0.008166144 31.91 0.007947003 0.00 0.000000000
11 Gifts 10.00 0.002803649 89.00 0.022537580 100.00 0.021825102 30.00 0.007450862 55.00 0.013697436 10.00 0.003242479
12 Groceries 233.33 0.065417547 372.68 0.094374215 398.37 0.086944660 424.40 0.105404855 397.25 0.098932845 342.11 0.110928451
13 Lunch 154.75 0.043386472 383.75 0.097177485 326.25 0.071204396 412.00 0.102325166 486.40 0.121135144 291.00 0.094356141
14 Maintenance 0.00 0.000000000 0.00 0.000000000 151.00 0.032955905 142.75 0.035453683 115.60 0.028789520 76.50 0.024804965
15 Medical Expenses 0.00 0.000000000 144.19 0.036513411 29.95 0.006536618 86.55 0.021495736 47.08 0.011725005 66.80 0.021659760
16 Miscellaneous 0.00 0.000000000 508.11 0.128669321 101.00 0.022043353 1051.50 0.261152698 1000.00 0.249044293 1008.00 0.326841890
17 Personal Care 30.00 0.008410948 30.00 0.007596937 90.00 0.019642592 30.00 0.007450862 120.00 0.029885315 30.00 0.009727437
18 Phone 0.00 0.000000000 38.40 0.009724079 38.45 0.008391752 38.90 0.009661284 41.11 0.010238211 41.11 0.013329831
19 Recreation 0.00 0.000000000 81.75 0.020701653 61.00 0.013313312 51.50 0.012790646 256.00 0.063755339 316.00 0.102462339
20 Rent 545.00 0.152798883 1746.70 0.442318990 743.75 0.162324199 749.70 0.186197031 761.60 0.189672133 765.00 0.248049649
21 Repair and Maintenance 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 65.00 0.021076114
22 Transportation 32.50 0.009111860 35.00 0.008863093 129.00 0.028154382 35.00 0.008692672 55.00 0.013697436 62.00 0.020103370
23 Travel 0.00 0.000000000 0.00 0.000000000 228.53 0.049876906 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000
I also encountered the following error while using cast on a single value column: it does not take into account the "value" parameter. So, even if i specify value = "percent" it still displays the values from "value" column.
在使用单个值列时，我还遇到了以下错误:它没有考虑到“值”参数。因此，即使我指定value = "percent"它仍然显示来自"value"列的值。
cast(expensesByMonth, expense_type ~ month, fun.aggregate = sum, value = "percent")
4 个解决方案
#1
20
Your best option is to reshape your data to long format, using melt, and then to dcast:
你最好的选择是将你的数据重新格式化为长格式，使用熔体，然后再进行dcast:
library(reshape2)
meltExpensesByMonth <- melt(expensesByMonth, id.vars=1:2)
dcast(meltExpensesByMonth, expense_type ~ month + variable, fun.aggregate = sum)
The first few lines of output:
输出的前几行:
expense_type 2012-02-01_value 2012-02-01_percent 2012-03-01_value 2012-03-01_percent
1 Adjustment 442.37 0.124025031 2.00 0.0005064625
2 Bank Service Charge 200.00 0.056072985 200.00 0.0506462461
3 Cable 21.33 0.005980184 36.33 0.0091998906
4 Charity 0.00 0.000000000 0.00 0.0000000000
#2
18
data.table can cast on multiple value.var variables. This is quite direct (and efficient).
数据。表可以对多个值进行强制转换。var变量。这是相当直接的(和有效的)。
Therefore:
因此:
library(data.table) # v1.9.5+
dcast(setDT(expensesByMonth), expense_type ~ month, value.var = c("value", "percent"))
#3
3
I prefer the tabulate function in package tables for this. It requires factors, but this is anyway a good idea with the type of data you have.
为此，我更喜欢在包表中使用表格函数。它需要因子，但无论如何，这对于你拥有的数据类型来说是个好主意。
library(tables)
expensesByMonth$month= as.factor(expensesByMonth$month)
expensesByMonth$expense_type= as.factor(expensesByMonth$expense_type)
tabular(expense_type~(month)*(value+percent)*(sum),data=expensesByMonth)
# Optional formatting
tabular(expense_type~month*
((Format(digits=1))*value+(Format(digits=3))*percent)*sum,
data=expensesByMonth)
Partial output:
部分输出:
value percent value percent value percent
expense_type sum sum sum sum sum sum
Adjustment 442 0.124025 2 0.000506 16 0.003573
Bank Service Charge 200 0.056073 200 0.050646 200 0.043650
Cable 21 0.005980 36 0.009200 0 0.000000
#4
2
As this question is often visited, it deserves a complete base R answer too in my opinion. The reshape-function from base R is quite versatile and can easily be applied to this problem as well:
由于这个问题经常被提及，在我看来，它也应该得到一个完整的基本答案。基于R的重构函数非常通用，可以很容易地应用于这个问题:
expenses <- reshape(expensesByMonth, idvar = 'expense_type', direction = 'wide',
timevar = 'month', sep = '_')
The cells with NA-values can be replaced with 0 with:
na -值的单元格可以用0替换为:
expenses[is.na(expenses)] <- 0
which gives (ordered by expense_type to make it easier to compare with the desired output):
它给出(根据expense_type排序，以便与所需的输出进行比较):
> expenses[order(expenses$expense_type),] expense_type value_2012-02-01 percent_2012-02-01 value_2012-03-01 percent_2012-03-01 value_2012-04-01 percent_2012-04-01 value_2012-05-01 percent_2012-05-01 value_2012-06-01 percent_2012-06-01 value_2012-07-01 percent_2012-07-01 1 Adjustment 442.37 0.124025031 2.00 0.0005064625 16.37 0.003572769 0.00 0.000000000 10.00 0.002490443 0.00 0.000000000 2 Bank Service Charge 200.00 0.056072985 200.00 0.0506462461 200.00 0.043650205 200.00 0.049672410 200.00 0.049808859 0.00 0.000000000 3 Cable 21.33 0.005980184 36.33 0.0091998906 0.00 0.000000000 39.05 0.009698538 16.00 0.003984709 0.00 0.000000000 67 Charity 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 32.59 0.008116353 0.00 0.000000000 30 Clothes 0.00 0.000000000 0.00 0.0000000000 806.90 0.176106751 237.00 0.058861806 149.81 0.037309325 0.00 0.000000000 4 Clubbing 75.00 0.021027369 206.55 0.0523049107 324.81 0.070890115 40.00 0.009934482 0.00 0.000000000 0.00 0.000000000 32 Computer 0.00 0.000000000 0.00 0.0000000000 756.00 0.164997774 283.83 0.070492601 100.00 0.024904429 10.54 0.003417573 5 Dining 22.50 0.006308211 74.50 0.0188657267 80.50 0.017569207 141.32 0.035098525 80.00 0.019923543 0.00 0.000000000 6 Education 1800.00 0.504656861 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 60.00 0.014942658 0.00 0.000000000 52 Electric 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 32.88 0.008166144 31.91 0.007947003 0.00 0.000000000 7 Gifts 10.00 0.002803649 89.00 0.0225375795 100.00 0.021825102 30.00 0.007450862 55.00 0.013697436 10.00 0.003242479 8 Groceries 233.33 0.065417547 372.68 0.0943742150 398.37 0.086944660 424.40 0.105404855 397.25 0.098932845 342.11 0.110928451 9 Lunch 154.75 0.043386472 383.75 0.0971774847 326.25 0.071204396 412.00 0.102325166 486.40 0.121135144 291.00 0.094356141 37 Maintenance 0.00 0.000000000 0.00 0.0000000000 151.00 0.032955905 142.75 0.035453683 115.60 0.028789520 76.50 0.024804965 21 Medical Expenses 0.00 0.000000000 144.19 0.0365134111 29.95 0.006536618 86.55 0.021495736 47.08 0.011725005 66.80 0.021659760 22 Miscellaneous 0.00 0.000000000 508.11 0.1286693205 101.00 0.022043353 1051.50 0.261152698 1000.00 0.249044293 1008.00 0.326841890 10 Personal Care 30.00 0.008410948 30.00 0.0075969369 90.00 0.019642592 30.00 0.007450862 120.00 0.029885315 30.00 0.009727437 24 Phone 0.00 0.000000000 38.40 0.0097240793 38.45 0.008391752 38.90 0.009661284 41.11 0.010238211 41.11 0.013329831 25 Recreation 0.00 0.000000000 81.75 0.0207016531 61.00 0.013313312 51.50 0.012790646 256.00 0.063755339 316.00 0.102462339 11 Rent 545.00 0.152798883 1746.70 0.4423189903 743.75 0.162324199 749.70 0.186197031 761.60 0.189672133 765.00 0.248049649 95 Repair and Maintenance 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 65.00 0.021076114 12 Transportation 32.50 0.009111860 35.00 0.0088630931 129.00 0.028154382 35.00 0.008692672 55.00 0.013697436 62.00 0.020103370 45 Travel 0.00 0.000000000 0.00 0.0000000000 228.53 0.049876906 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000
You could also achieve this with the tidyverse:
你也可以用tidyverse来达到这个目的:
library(dplyr)
library(tidyr)
expensesByMonth %>%
gather(k, v, 3:4) %>%
unite(km, k, month) %>%
spread(km, v, fill = 0)
#1
20
Your best option is to reshape your data to long format, using melt, and then to dcast:
你最好的选择是将你的数据重新格式化为长格式，使用熔体，然后再进行dcast:
library(reshape2)
meltExpensesByMonth <- melt(expensesByMonth, id.vars=1:2)
dcast(meltExpensesByMonth, expense_type ~ month + variable, fun.aggregate = sum)
The first few lines of output:
输出的前几行:
expense_type 2012-02-01_value 2012-02-01_percent 2012-03-01_value 2012-03-01_percent
1 Adjustment 442.37 0.124025031 2.00 0.0005064625
2 Bank Service Charge 200.00 0.056072985 200.00 0.0506462461
3 Cable 21.33 0.005980184 36.33 0.0091998906
4 Charity 0.00 0.000000000 0.00 0.0000000000
#2
18
data.table can cast on multiple value.var variables. This is quite direct (and efficient).
数据。表可以对多个值进行强制转换。var变量。这是相当直接的(和有效的)。
Therefore:
因此:
library(data.table) # v1.9.5+
dcast(setDT(expensesByMonth), expense_type ~ month, value.var = c("value", "percent"))
#3
3
I prefer the tabulate function in package tables for this. It requires factors, but this is anyway a good idea with the type of data you have.
为此，我更喜欢在包表中使用表格函数。它需要因子，但无论如何，这对于你拥有的数据类型来说是个好主意。
library(tables)
expensesByMonth$month= as.factor(expensesByMonth$month)
expensesByMonth$expense_type= as.factor(expensesByMonth$expense_type)
tabular(expense_type~(month)*(value+percent)*(sum),data=expensesByMonth)
# Optional formatting
tabular(expense_type~month*
((Format(digits=1))*value+(Format(digits=3))*percent)*sum,
data=expensesByMonth)
Partial output:
部分输出:
value percent value percent value percent
expense_type sum sum sum sum sum sum
Adjustment 442 0.124025 2 0.000506 16 0.003573
Bank Service Charge 200 0.056073 200 0.050646 200 0.043650
Cable 21 0.005980 36 0.009200 0 0.000000
#4
2
As this question is often visited, it deserves a complete base R answer too in my opinion. The reshape-function from base R is quite versatile and can easily be applied to this problem as well:
由于这个问题经常被提及，在我看来，它也应该得到一个完整的基本答案。基于R的重构函数非常通用，可以很容易地应用于这个问题:
expenses <- reshape(expensesByMonth, idvar = 'expense_type', direction = 'wide',
timevar = 'month', sep = '_')
The cells with NA-values can be replaced with 0 with:
na -值的单元格可以用0替换为:
expenses[is.na(expenses)] <- 0
which gives (ordered by expense_type to make it easier to compare with the desired output):
它给出(根据expense_type排序，以便与所需的输出进行比较):
> expenses[order(expenses$expense_type),] expense_type value_2012-02-01 percent_2012-02-01 value_2012-03-01 percent_2012-03-01 value_2012-04-01 percent_2012-04-01 value_2012-05-01 percent_2012-05-01 value_2012-06-01 percent_2012-06-01 value_2012-07-01 percent_2012-07-01 1 Adjustment 442.37 0.124025031 2.00 0.0005064625 16.37 0.003572769 0.00 0.000000000 10.00 0.002490443 0.00 0.000000000 2 Bank Service Charge 200.00 0.056072985 200.00 0.0506462461 200.00 0.043650205 200.00 0.049672410 200.00 0.049808859 0.00 0.000000000 3 Cable 21.33 0.005980184 36.33 0.0091998906 0.00 0.000000000 39.05 0.009698538 16.00 0.003984709 0.00 0.000000000 67 Charity 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 32.59 0.008116353 0.00 0.000000000 30 Clothes 0.00 0.000000000 0.00 0.0000000000 806.90 0.176106751 237.00 0.058861806 149.81 0.037309325 0.00 0.000000000 4 Clubbing 75.00 0.021027369 206.55 0.0523049107 324.81 0.070890115 40.00 0.009934482 0.00 0.000000000 0.00 0.000000000 32 Computer 0.00 0.000000000 0.00 0.0000000000 756.00 0.164997774 283.83 0.070492601 100.00 0.024904429 10.54 0.003417573 5 Dining 22.50 0.006308211 74.50 0.0188657267 80.50 0.017569207 141.32 0.035098525 80.00 0.019923543 0.00 0.000000000 6 Education 1800.00 0.504656861 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 60.00 0.014942658 0.00 0.000000000 52 Electric 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 32.88 0.008166144 31.91 0.007947003 0.00 0.000000000 7 Gifts 10.00 0.002803649 89.00 0.0225375795 100.00 0.021825102 30.00 0.007450862 55.00 0.013697436 10.00 0.003242479 8 Groceries 233.33 0.065417547 372.68 0.0943742150 398.37 0.086944660 424.40 0.105404855 397.25 0.098932845 342.11 0.110928451 9 Lunch 154.75 0.043386472 383.75 0.0971774847 326.25 0.071204396 412.00 0.102325166 486.40 0.121135144 291.00 0.094356141 37 Maintenance 0.00 0.000000000 0.00 0.0000000000 151.00 0.032955905 142.75 0.035453683 115.60 0.028789520 76.50 0.024804965 21 Medical Expenses 0.00 0.000000000 144.19 0.0365134111 29.95 0.006536618 86.55 0.021495736 47.08 0.011725005 66.80 0.021659760 22 Miscellaneous 0.00 0.000000000 508.11 0.1286693205 101.00 0.022043353 1051.50 0.261152698 1000.00 0.249044293 1008.00 0.326841890 10 Personal Care 30.00 0.008410948 30.00 0.0075969369 90.00 0.019642592 30.00 0.007450862 120.00 0.029885315 30.00 0.009727437 24 Phone 0.00 0.000000000 38.40 0.0097240793 38.45 0.008391752 38.90 0.009661284 41.11 0.010238211 41.11 0.013329831 25 Recreation 0.00 0.000000000 81.75 0.0207016531 61.00 0.013313312 51.50 0.012790646 256.00 0.063755339 316.00 0.102462339 11 Rent 545.00 0.152798883 1746.70 0.4423189903 743.75 0.162324199 749.70 0.186197031 761.60 0.189672133 765.00 0.248049649 95 Repair and Maintenance 0.00 0.000000000 0.00 0.0000000000 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000 65.00 0.021076114 12 Transportation 32.50 0.009111860 35.00 0.0088630931 129.00 0.028154382 35.00 0.008692672 55.00 0.013697436 62.00 0.020103370 45 Travel 0.00 0.000000000 0.00 0.0000000000 228.53 0.049876906 0.00 0.000000000 0.00 0.000000000 0.00 0.000000000
You could also achieve this with the tidyverse:
你也可以用tidyverse来达到这个目的:
library(dplyr)
library(tidyr)
expensesByMonth %>%
gather(k, v, 3:4) %>%
unite(km, k, month) %>%
spread(km, v, fill = 0)