为什么我不能索引mysql返回的数组?(复制)

Possible Duplicate:
Access array returned by a function in php

可能的重复:访问php中函数返回的数组

The code:

代码:

$cnt = mysql_fetch_row(mysql_query("SELECT FOUND_ROWS()"))[0]

Is giving the error:

给的错误:

Parse error: syntax error, unexpected '[' in index.php on line 117

解析错误:语法错误，意外的“[”在索引中。php在第117行

Same for:

同样的为:

$cnt = (mysql_fetch_row(mysql_query("SELECT FOUND_ROWS()")))[0]

This code:

这段代码:

$cnt = mysql_fetch_row(mysql_query("SELECT FOUND_ROWS()"));
$cnt = $cnt[0];

is working fine.

工作正常。

What's going on here?

这是怎么回事?

1 个解决方案

#1

It isn't just a problem with mysql_query--rather, it's an idiosyncracy in the way that PHP <5.4 handles bracket notation. The following will fail, as well:

这不仅仅是mysql_query的问题——更确切地说，它是PHP <5.4处理括号表示法的一种特性。以下也将失败:

function get_array() {
  return array('foo', 'bar');
}

echo get_array()[0];

But, as you observed, setting the result before attempting to retrieve an element works fine:

但是，正如您所观察到的，在尝试检索元素之前设置结果是可行的:

$arr = get_array();
echo $arr[0];

#1