I created an array and put the value into array as follow
我创建了一个数组并将值放入数组中,如下所示
int *ptr_int;
int list_int[10];
int i;
for (i=0; i<10; i++)
list_int[i] = i + 1;
and I assign a value into list_int
array like this
我像这样在list_int数组中赋值
list_int[17] = 18;
When I tried to get the count of array as follow
当我试图得到数组的数量如下
int size = sizeof(list_int ) / sizeof( int );
printf( "The size of int is %d.\n", size);
the result is only 10
.
结果只有10个。
How could I get the array room count?
我怎么能得到阵列室数?
4 个解决方案
#1
6
the result is only 10.
结果只有10个。
That's the real size. Assigning to list_int[17]
is undefined behavior, and it does not magically extend the array.
这是真正的大小。分配给list_int [17]是未定义的行为,它不会神奇地扩展数组。
#2
1
You have already defined the max size of your array as 10 with the following definition
您已使用以下定义将阵列的最大大小定义为10
int list_int[10];
You can not assign value to list_int[17]
. Becacuse list_int[17]
is out of the memory of the array list_int[10]
that you have defined.
您无法为list_int分配值[17]。 Becacuse list_int [17]超出了你定义的数组list_int [10]的内存。
You can only assign value to the element from 0 .. 9
您只能为0到9中的元素赋值
#3
1
list_int[17] = 18;
This is undefined behavior because the array size is only 10.
这是未定义的行为,因为数组大小仅为10。
Note that with the exception of variable length arrays, sizeof
operator is a compile time operator. The result of sizeof(list_int )
and sizeof(int)
are determined in compile time.
请注意,除了可变长度数组之外,sizeof运算符是编译时运算符。 sizeof(list_int)和sizeof(int)的结果在编译时确定。
To implement an array with dynamic size, you need to allocate the array dynamically, you may find realloc
pretty helpful.
要实现具有动态大小的数组,您需要动态分配数组,您可能会发现realloc非常有用。
#4
1
To Create Dynamic arrays ( allocated at run time )
创建动态数组(在运行时分配)
int n;
scanf("%d",&n); // read n from the user at run time
int* x=(int*)malloc(sizeof(int)*n); // where n is the number of elements you need to allocate
////// after that you can access the array (x) using indexer
///// reading loop
for(int i=0;i<n;i++)
scanf("%d",&x[i]);
===============================================================================
================================================== =============================
Note: if you need more dynamic data structure which can allocate memory for each entry you can use linked lists
注意:如果您需要更多动态数据结构,可以为每个条目分配内存,则可以使用链接列表
#1
6
the result is only 10.
结果只有10个。
That's the real size. Assigning to list_int[17]
is undefined behavior, and it does not magically extend the array.
这是真正的大小。分配给list_int [17]是未定义的行为,它不会神奇地扩展数组。
#2
1
You have already defined the max size of your array as 10 with the following definition
您已使用以下定义将阵列的最大大小定义为10
int list_int[10];
You can not assign value to list_int[17]
. Becacuse list_int[17]
is out of the memory of the array list_int[10]
that you have defined.
您无法为list_int分配值[17]。 Becacuse list_int [17]超出了你定义的数组list_int [10]的内存。
You can only assign value to the element from 0 .. 9
您只能为0到9中的元素赋值
#3
1
list_int[17] = 18;
This is undefined behavior because the array size is only 10.
这是未定义的行为,因为数组大小仅为10。
Note that with the exception of variable length arrays, sizeof
operator is a compile time operator. The result of sizeof(list_int )
and sizeof(int)
are determined in compile time.
请注意,除了可变长度数组之外,sizeof运算符是编译时运算符。 sizeof(list_int)和sizeof(int)的结果在编译时确定。
To implement an array with dynamic size, you need to allocate the array dynamically, you may find realloc
pretty helpful.
要实现具有动态大小的数组,您需要动态分配数组,您可能会发现realloc非常有用。
#4
1
To Create Dynamic arrays ( allocated at run time )
创建动态数组(在运行时分配)
int n;
scanf("%d",&n); // read n from the user at run time
int* x=(int*)malloc(sizeof(int)*n); // where n is the number of elements you need to allocate
////// after that you can access the array (x) using indexer
///// reading loop
for(int i=0;i<n;i++)
scanf("%d",&x[i]);
===============================================================================
================================================== =============================
Note: if you need more dynamic data structure which can allocate memory for each entry you can use linked lists
注意:如果您需要更多动态数据结构,可以为每个条目分配内存,则可以使用链接列表