I've got this query:
我有这个问题:
cities = ShippingPrice.objects.filter(city1__name__icontains=request.REQUEST.get('city','')).values_list('city1__id','city1__name').order_by('city1__name').distinct()
Which returns a list of lists. It would be nice instead of doing .values_list('city1__id','city1__name')
I could write:
返回列表列表。这会很好而不是做.values_list('city1__id','city1__name')我可以写:
.values_list({'id':'city1__id','name':'city1__name'})
And it would return me back a lists of dicts, like
它会让我回到一个dicts列表,比如
[{'id':4135,'name':'Seattle'},{'id':4154,'name':'Vancouver'}]
Are there any existing methods to do that?
有没有现成的方法呢?
I'm looking through the Django source code, but I'd have no idea how to override this:
我正在浏览Django源代码,但我不知道如何覆盖它:
def values_list(self, *fields, **kwargs):
flat = kwargs.pop('flat', False)
if kwargs:
raise TypeError('Unexpected keyword arguments to values_list: %s'
% (kwargs.keys(),))
if flat and len(fields) > 1:
raise TypeError("'flat' is not valid when values_list is called with more than one field.")
return self._clone(klass=ValuesListQuerySet, setup=True, flat=flat,
_fields=fields)