如何从xml节点查询值?

时间:2021-01-05 01:27:53

i have a table that contains an XML column:

我有一个包含XML列的表:

CREATE TABLE Batches( 
   BatchID int,
   RawXml xml 
)

The xml contains items such as:

xml包含以下内容:

<GrobReportXmlFileXmlFile>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>

What i want is to generate a set, that contains:

我想要的是生成一个集合,它包含:

OrganizationReportReferenceNumber  OrganizationNumber
=================================  ==================
1                                  4
2                                  4
3                                  4
4                                  4

i've tried:

我试过了:

SELECT 
    foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
    foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM CDRBatches.RawXML.query('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') foo

but that doesn't work. i've tried:

但这并不工作。我试过了:

SELECT 
    foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
    foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM RawXML.nodes('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') bar(foo)

But that doesn't work. The XPath expression

但这并不工作。XPath表达式

/GrobReportXmlFileXmlFile/GrobReport/ReportHeader

is correct; in any other xml system it returns:

是正确的;在任何其他xml系统中,它返回:

<ReportHeader>
    <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>

So, it's obvious from my queries that i'd like to see. After reading a dozen Stackover questions and answers, i'm no closer to solving the problem.

从我的查询中可以明显看出我很想看到。读了一堆问题和答案之后,我离解决问题更近了一步。

3 个解决方案

#1


22  

SELECT  b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    Batches b
CROSS APPLY b.RawXml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol);

Demo: SQLFiddle

演示:SQLFiddle

#2


2  

This works, been tested...

其工作原理,经过测试……

SELECT  n.c.value('OrganizationReportReferenceIdentifier[1]','varchar(128)') AS 'OrganizationReportReferenceNumber',  
        n.c.value('(OrganizationNumber)[1]','varchar(128)') AS 'OrganizationNumber'
FROM    Batches t
Cross   Apply RawXML.nodes('/GrobXmlFile/Grob/ReportHeader') n(c)  

#3


1  

Try this:

试试这个:

SELECT RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationReportReferenceIdentifier/node())[1]','varchar(50)') AS ReportIdentifierNumber,
       RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationNumber/node())[1]','int') AS OrginazationNumber
FROM Batches

#1


22  

SELECT  b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    Batches b
CROSS APPLY b.RawXml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol);

Demo: SQLFiddle

演示:SQLFiddle

#2


2  

This works, been tested...

其工作原理,经过测试……

SELECT  n.c.value('OrganizationReportReferenceIdentifier[1]','varchar(128)') AS 'OrganizationReportReferenceNumber',  
        n.c.value('(OrganizationNumber)[1]','varchar(128)') AS 'OrganizationNumber'
FROM    Batches t
Cross   Apply RawXML.nodes('/GrobXmlFile/Grob/ReportHeader') n(c)  

#3


1  

Try this:

试试这个:

SELECT RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationReportReferenceIdentifier/node())[1]','varchar(50)') AS ReportIdentifierNumber,
       RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationNumber/node())[1]','int') AS OrginazationNumber
FROM Batches