在javascript中创建一个Json对象

I am in process to validate a form where i need to show certain radio buttons and user need to select them based on some rules,how many number of radio buttons can be created is dynamic so i can not do validation on server side not can write a predefined java-script code for that.

我正在验证一个表单，我需要显示某些单选按钮，用户需要根据一些规则选择它们，可以创建多少个单选按钮是动态的，所以我不能在服务器端进行验证不能写一个预定义的java脚本代码。

each of the radio buttons will be divided in to groups say required and than further down they can be grouped like center,left, right etc, so from each group user need to select one value, so the structure comes out like this

每个单选按钮将被分成所需的组，而不是向下，它们可以分组为中心，左，右等，所以从每个组用户需要选择一个值，所以结构就像这样

-Main Group (if block needs to validate based on this e.g if key=required should validate)
  |
  Sub-group (say left, right etc)
   |
   number of radio buttons based on the sub-group

So the main group key can be used to decide if validation should be done on that or not and based on the sub-group key i can decide what all values will be there and needs to be validate

所以主组密钥可用于决定是否应该对此进行验证，并且基于子组密钥，我可以决定所有值将在那里并且需要验证

i was planning to create a JSON object on page rendering time like

我打算在页面渲染时创建一个JSON对象

{"required": [
        {"center": "id1,id2,id3"},
        {"left": "id1,id2,id3"}
      ]
  "optional": [
        {"center": "id1,id2,id3"},
        {"left": "id1,id2,id3"}
      ]
};

i am not sure if the structure i am thinking is right and how to create it in java script? like i have a external loop for key and than one more loop for the sub-group and finally for the buttons in the sub-group,

我不确定我认为的结构是否正确以及如何在java脚本中创建它？就像我有一个外部循环的键，而不是一个循环的子组，最后是子组中的按钮，

 for(main group key){
     for(subgroup key){
       for(list of radio button under subgroup key)
}
  }

but not sure how to create a right structure so that i can parse it later with jquery and use that for validation.

但不知道如何创建一个正确的结构，以便我可以稍后使用jquery解析它并将其用于验证。

Any help in this will really be appreciated.

任何帮助都将非常感激。

1 个解决方案

#1

In javascript. You can use JSON.stringify(myObject, replacer);

在javascript中。您可以使用JSON.stringify（myObject，replacer）;

For example.

例如。

create on javascript object like this

像这样在javascript对象上创建

var myObject={};

now after creating javascript object you can convert it into JSON structure like this

现在，在创建javascript对象后，您可以将其转换为这样的JSON结构

var myJsonText=JSON.stringify(myObject);

NOTE: replacer is optional

注意：替换器是可选的

Now if you want to convert it in JSON Object Use JSON.parse method

现在，如果要在JSON对象中使用JSON.parse方法转换它

myJsonObject=JSON.parse(myJsonText)

#1