There are already posts talking about this, but I am still not able to figure out my problem.
已有帖子谈论这个,但我仍然无法弄清楚我的问题。
I am accessing my database and am converting the response into a JSON object - that part is working fine. Here is the code for that. joArray
now has the data I need.
我正在访问我的数据库,并将响应转换为JSON对象 - 该部分工作正常。这是代码。 joArray现在拥有我需要的数据。
//Convert data to json object
let joArray : NSArray
do {
joArray = try JSONSerialization.jsonObject(with: data, options: []) as! NSArray
}
catch {
print(responseString)
print("error trying to convert data to JSON")
return
}
If I print out joArray . . .
如果我打印出joArray。 。 。
print(joArray)
. . . this is what I get.
。 。 。这就是我得到的。
(
{
FirstName = Bob;
},
{
FirstName = Bill;
}
)
How can I put this data into a swift array so that it looks like this?
如何将这些数据放入一个快速数组中,使它看起来像这样?
let FirstNameArray = ["Bob", "Bill"]
FirstName will always be in the same position, but there will be varying numbers of users (Bob, Bill, Mary, etc.).
FirstName将始终处于相同的位置,但会有不同数量的用户(Bob,Bill,Mary等)。
1 个解决方案
#1
2
You will make life easier for yourself if you use a native Swift array instead. So, start by changing your array definition:
如果您使用原生Swift数组,您将使自己的生活更轻松。因此,首先要更改数组定义:
let joArray: [[String: Any]]
do {
joArray = try JSONSerialization.jsonObject(with: data, options: []) as! [[String: Any]]
} catch {
// etc...
}
Now, it's straightforward to construct the required array:
现在,构建所需的数组非常简单:
let FirstNameArray = swiftArray.flatMap { $0["FirstName"] }
You should use flatMap
, rather than map
, because the given array item might not have a property called "FirstName"
.
您应该使用flatMap而不是map,因为给定的数组项可能没有名为“FirstName”的属性。
#1
2
You will make life easier for yourself if you use a native Swift array instead. So, start by changing your array definition:
如果您使用原生Swift数组,您将使自己的生活更轻松。因此,首先要更改数组定义:
let joArray: [[String: Any]]
do {
joArray = try JSONSerialization.jsonObject(with: data, options: []) as! [[String: Any]]
} catch {
// etc...
}
Now, it's straightforward to construct the required array:
现在,构建所需的数组非常简单:
let FirstNameArray = swiftArray.flatMap { $0["FirstName"] }
You should use flatMap
, rather than map
, because the given array item might not have a property called "FirstName"
.
您应该使用flatMap而不是map,因为给定的数组项可能没有名为“FirstName”的属性。