将XML转换为Json并从转换后的Json中删除XML声明

I have the following XML file that I need to convert to JSON. I am able to convert it to Json using Newtonsoft library but it includes xml declaration part also.How can i skip xml declaration part and convert remaining file to json?

我有以下XML文件，我需要转换为JSON。我能够使用Newtonsoft库将其转换为Json，但它也包含xml声明部分。如何跳过xml声明部分并将剩余文件转换为json？

I am using below code(C#) to convert it.

我使用下面的代码（C＃）来转换它。

JsonConvert.SerializeXmlNode(employeeXMLDoc)

Sample xml input

示例xml输入

<?xml version="1.0" encoding="UTF-8" ?>
<Employee>
  <EmployeeID>1</EmployeeID>
  <EmployeeName>XYZ</EmployeeName>
</Employee>

Json Output

Json输出

{"?xml":{"@version":"1.0","@encoding":"UTF-8"},"Employee":{"EmployeeID":"1","EmployeeName":"XYZ"}}

2 个解决方案

#1

You could remove the first child from the XmlDocument:

您可以从XmlDocument中删除第一个子项：

employeeXMLDoc.RemoveChild(employeeXMLDoc.FirstChild);

And then serialize as you're doing now.

然后按照你现在的顺序进行序列化。

#2

Or in a single line:

或者在一行中：

JsonConvert.SerializeXmlNode(employeeXMLDoc.FirstChild.NextSibling);

JsonConvert.SerializeXmlNode（employeeXMLDoc.FirstChild.NextSibling）;

#1