Notepad++找到并替换Regex。

This is my coding:

这是我的编码：

alpha = ["first", 55, 28]
beta  = ["second", 89, 09]
gamma = ["third", 99, 40]

And this is my intended outcome:

这是我的预期结果：

first", 55, 28]
second", 89, 09]
third", 99, 40]

I've tried replace the regex of ^.*?" with empty. But why I get this instead?:

我尝试用空替换^。*？“的正则表达式。但为什么我这样做呢？”

, 55, 28]
, 89, 09]
, 99, 40]

3 个解决方案

#1

Find and replace with ^.*?\["

查找并替换为^。*？\ [“

Input

输入

alpha = ["first", 55, 28]
beta  = ["second", 89, 09]
gamma = ["third", 99, 40]

Result

结果

first", 55, 28]
second", 89, 09]
third", 99, 40]

---

The problem with ^.*?" is that it's replacing all the content one by one

^。*？“的问题在于它正在逐个替换所有内容

1. You're starting with this content

   你是从这个内容开始的

   alpha = ["first", 55, 28]
   beta  = ["second", 89, 09]
   gamma = ["third", 99, 40]
   

2. After first replace (as expected), the content becomes this,

   在第一次替换（如预期）后，内容变为此，

   first", 55, 28]
   beta  = ["second", 89, 09]
   gamma = ["third", 99, 40]
   

3. Now, in the next replace, the cursor is still at the start of the line. Notice that there is one more double quote " in this line (just after the text first), thus the RegEx is matched again and so it will again replace everything before the first double quote

   现在，在下一次替换中，光标仍然在行的开头。请注意，在此行中（在文本首先之后）还有一个双引号，因此RegEx再次匹配，因此它将再次替换第一个双引号之前的所有内容

   , 55, 28]
   beta  = ["second", 89, 09]
   gamma = ["third", 99, 40]
   

4. When you continue in this manner, you'll get the output as:

   当您以这种方式继续时，您将获得输出：

   , 55, 28]
   , 89, 09]
   , 99, 40]
   

And so use ^.*?\[" instead of ^.*?"

所以使用^。*？\ [“而不是^。*？”

---

EDIT

编辑

If there are any chances that you have arrays inside your parent array, then you can use ^.*?\=\s*\[\s*".
This regex will also deal with whitespace character.

如果你的父数组中有数组，那么你可以使用^。*？\ = \ s * \ [\ s *“。这个正则表达式也将处理空白字符。

Input

输入

alpha = ["first", 55, 28]
beta  =   ["second", 89, 09]
gamma =      ["third", 99, 40]
delta = ["fourth", ["55"], 28]

After replace

更换后

first", 55, 28]
second", 89, 09]
third", 99, 40]
fourth", ["55"], 28]

#2

Use this regex:

使用这个正则表达式：

^[^"]*"(.*)$

The quantity in parenthesis is called a capture group, because its contents will be captured for each line in your file for which the replace operation is run. You want to retain this captured material, so use a replacement of \1 in the dialog box.

括号中的数量称为捕获组，因为将为运行替换操作的文件中的每一行捕获其内容。您希望保留此捕获的材质，因此请在对话框中使用\ 1替换\ 1。

Here is a screen capture of how to use it:

以下是如何使用它的屏幕截图：

#3

you could try this .*=\s?\[. of course all setting as @TimBiegeleisen showed.

你可以试试这个。* = \ s？\ [。当然所有设置为@TimBiegeleisen都显示出来。