无限级树(Java递归)

时间:2011-12-03 03:19:51
【文件属性】:

文件名称:无限级树(Java递归)

文件大小:7KB

文件格式:TXT

更新时间:2011-12-03 03:19:51

堆在树

无限级树(Java递归) 2007-02-08 10:26 这几天,用java写了一个无限极的树,递归写的,可能代码不够简洁,性能不够好,不过也算是练习,这几天再不断改进。前面几个小图标的判断,搞死我了。 package com.nickol.servlet; import java.io.IOException; import java.io.PrintWriter; import java.sql.Connection; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.util.ArrayList; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.nickol.utility.DB; public class category extends HttpServlet { /** * The doGet method of the servlet.
* * This method is called when a form has its tag value method equals to get. * * @param request the request send by the client to the server * @param response the response send by the server to the client * @throws ServletException if an error occurred * @throws IOException if an error occurred */ public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setCharacterEncoding("utf-8"); response.setContentType("text/html"); PrintWriter out = response.getWriter(); out .println(""); out.println(""); out.println(" Category" + "" + "" + ""); out.println(" "); out.println(showCategory(0,0,new ArrayList(),"0")); out.println(" "); out.println(""); out.flush(); out.close(); } public String showCategory(int i,int n,ArrayList frontIcon,String countCurrent){ int countChild = 0; n++; String webContent = new String(); ArrayList temp = new ArrayList(); try{ Connection conn = DB.GetConn(); PreparedStatement ps = DB.GetPs("select * from category where pid = ?", conn); ps.setInt(1, i); ResultSet rs = DB.GetRs(ps); if(n==1){ if(rs.next()){ webContent += "";//插入结尾的减号 temp.add(new Integer(0)); } webContent += " ";//插入站点图标 webContent += rs.getString("cname"); webContent += "
\n"; webContent += showCategory(Integer.parseInt(rs.getString("cid")),n,temp,"0"); } if(n==2){ webContent += "

\n"; }else{ webContent += "\n"; DB.CloseRs(rs); DB.ClosePs(ps); DB.CloseConn(conn); }catch(Exception e){ e.printStackTrace(); } return webContent; } public boolean checkChild(int i){ boolean child = false; try{ Connection conn = DB.GetConn(); PreparedStatement ps = DB.GetPs("select * from category where pid = ?", conn); ps.setInt(1, i); ResultSet rs = DB.GetRs(ps); if(rs.next()){ child = true; } DB.CloseRs(rs); DB.ClosePs(ps); DB.CloseConn(conn); }catch(Exception e){ e.printStackTrace(); } return child; } } --------------------------------------------------------------------- tree.js文件 function changeState(countCurrent,countChild){ var object = document.getElementById("level" + countCurrent + countChild); if(object.style.display=='none'){ object.style.display='block'; }else{ object.style.display='none'; } var cursor = document.getElementById("cursor" + countCurrent + countChild); if(cursor.src.indexOf("images/tree_minus.gif")>=0) {cursor.src="images/tree_plus.gif";} else if(cursor.src.indexOf("images/tree_minusbottom.gif")>=0) {cursor.src="images/tree_plusbottom.gif";} else if(cursor.src.indexOf("images/tree_plus.gif")>=0) {cursor.src="images/tree_minus.gif";} else {cursor.src="images/tree_minusbottom.gif";} var folder = document.getElementById("folder" + countCurrent + countChild); if(folder.src.indexOf("images/icon_folder_channel_normal.gif")>=0){ folder.src = "images/icon_folder_channel_open.gif"; }else{ folder.src = "images/icon_folder_channel_normal.gif"; }


网友评论

  • 还可以解决了问题
  • 多谢共享,不是我想要的,但同样感谢楼主。
  • 很好,不错,謝谢楼主分享,數据结构有待加强.
  • 谢谢楼主分享,虽然不是我想要的,不过还是谢谢@@@@