![[LeetCode] 557. Reverse Words in a String III 翻转字符串中的单词 III [LeetCode] 557. Reverse Words in a String III 翻转字符串中的单词 III](https://image.shishitao.com:8440/aHR0cHM6Ly9ia3FzaW1nLmlrYWZhbi5jb20vdXBsb2FkL2NoYXRncHQtcy5wbmc%2FIQ%3D%3D.png?!?w=700&webp=1)
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.
Example 1:
Input: "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"
Note: In the string, each word is separated by single space and there will not be any extra space in the string.
151. Reverse Words in a String ,186. Reverse Words in a String II 的类似题目,这题是让翻转字符串里的单词。
Python:One Place
class Solution(object):
def reverseWords(self, s): def reverse(s, begin, end):
for i in xrange((end - begin) // 2):
s[begin + i], s[end - 1 - i] = s[end - 1 - i], s[begin + i] s, i = list(s), 0
for j in xrange(len(s) + 1):
if j == len(s) or s[j] == ' ':
reverse(s, i, j)
i = j + 1
return "".join(s)
Python:New Array
class Solution2(object):
def reverseWords(self, s):
reversed_words = [word[::-1] for word in s.split(' ')]
return ' '.join(reversed_words)
C++:
class Solution {
public:
string reverseWords(string s) {
for (int i = 0, j = 0; j <= s.length(); ++j) {
if (j == s.length() || s[j] == ' ') {
reverse(s.begin() + i, s.begin() + j);
i = j + 1;
}
}
return s;
}
};
类似题目:
[LeetCode] 151. Reverse Words in a String 翻转字符串中的单词
[LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II