
第六题
5. (List)已知有一个Worker 类如下:
public class Worker
{ private int age;
private String name;
private double salary;
public Worker (){}
public Worker (String name, int age, double salary)
{ this.name = name;
this.age = age;
this.salary = salary; }
public int getAge() { return age; }
public void setAge(int age) { this.age = age; }
public String getName() { return name; }
public void setName(String name) { this.name = name; }
public double getSalary(){ return salary; }
public void setSalary(double salary){ this.salary = salary; }
public void work(){
System.out.println(name + “ work”); } }
完成下面的要求
1) 创建一个List,在List 中增加三个工人,基本信息如下:
姓名 年龄 工资
zhang3 18 3000
li4 25 3500
wang5 22 3200
2) 在li4 之前插入一个工人,信息为:姓名:zhao6,年龄:24,工资3300
3) 删除wang5 的信息
4) 利用for 循环遍历,打印List 中所有工人的信息
5) 利用迭代遍历,对List 中所有的工人调用work 方法。
package Test03; public class Worker {
private int age;
private String name;
private double salary; public Worker() {
} public Worker(String name, int age, double salary) {
this.name = name;
this.age = age;
this.salary = salary;
} public int getAge() {
return age;
} public void setAge(int age) {
this.age = age;
} public String getName() {
return name;
} public void setName(String name) {
this.name = name;
} public double getSalary() {
return salary;
} public void setSalary(double salary) {
this.salary = salary;
} public void work() {
System.out.println(name + " work");
}
@Override
public String toString() {
return "Worker [age=" + age + ", name=" + name + ", salary=" + salary + "]";
}
}
package Test03; import java.util.ArrayList;
import java.util.Iterator;
import java.util.List; public class TestWorker { public static void main(String[] args) { List<Worker> list = new ArrayList<>(); list.add(new Worker("张三",18,3000));
list.add(new Worker("李四",25,3500));
list.add(new Worker("王五",22,3200)); list.add(1,new Worker("赵六",24,3300)); list.remove(3); for(int i = 0;i<list.size();i++)
{
System.out.println(list.get(i));
} System.out.println("迭代器方式");
Iterator<Worker> it= list.iterator();
//判断能否移动
while(it.hasNext())
{
//移动指针到下一条数据,同事获取数据
Worker p=it.next();
System.out.println(p.toString()); }
} }