Tunnels HDU - 4856

时间:2023-03-09 08:00:29
Tunnels HDU - 4856

BFS寻找每个点到其他点的最小距离

再状压DP,DP[i][j] i二进制表示每个点的到达状态,j为当前所在点

#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<queue>
using namespace std;
#define pii pair<int,int>
#define CLR(a,b) memset(a,b,sizeof(a))
const int INF = 0x3f3f3f3f;
const int maxn = 40000;
char maze[20][20];
int vis[20][20];
int dis[20][20][20][20];
int dx[4] = {1,-1,0,0};
int dy[4] = {0,0,1,-1};
int n,m; int Dis[20][20][20][20]; struct Node{
int x,y;
int d;
Node(int x,int y,int d){
this->x = x;
this->y = y;
this->d = d;
}
};
queue<Node> Queue; void bfs(int x,int y)
{
vis[x][y] = 1;
dis[x][y][x][y] = 0;
Queue.push(Node(x,y,0));
while(Queue.size()){
int nx = Queue.front().x;
int ny = Queue.front().y;
int nd = Queue.front().d;
Queue.pop();
for(int i=0;i<4;i++){
if(nx + dx[i] >=1 && nx + dx[i] <=n && ny + dy[i] >=1 && ny + dy[i] <= n){
if(!vis[nx + dx[i]][ny + dy[i]] && maze[nx + dx[i]][ny + dy[i]] == '.'){
dis[x][y][nx + dx[i]][ny + dy[i]] = nd + 1;
vis[nx + dx[i]][ny + dy[i]] = 1;
Queue.push(Node(nx + dx[i],ny + dy[i],nd + 1));
}
}
}
}
} int dp[maxn][20];
int POW[20];
int mm[20][5];
int flag = 0; void solve()
{
POW[0] = 1;
for(int i=1;i<20;i++){
POW[i] = POW[i-1]*2;
} CLR(dp,0x3f);
for(int i=0;i<m;i++)
dp[1<<i][i] = 0; for(int i=1;i<POW[m];i++){
for(int j=0;j<m;j++){
if((i&POW[j]) == POW[j]){ int n = i^POW[j];
for(int k=0;k<m;k++){
if( (n&POW[k]) == POW[k]){
int a = mm[k][3];
int b = mm[k][4];
int aa = mm[j][1];
int bb = mm[j][2]; dp[i][j] = min(dp[n][k] + dis[a][b][aa][bb],dp[i][j]);
// cout<<dp[i][j]<<endl;
}
}
}
}
} } int main()
{
// freopen("in.txt","r",stdin);
while(cin>>n>>m){
for(int i=1;i<=n;i++){
scanf("%s",maze[i]+1);
}
for(int i=0;i<20;i++) for(int j=0;j<20;j++) for(int k=0;k<20;k++) for(int l=0;l<20;l++) dis[i][j][k][l] = INF;
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
if(maze[i][j] == '.'){
CLR(vis,0);
bfs(i,j);
}
}
}
for(int i=0;i<m;i++){
cin>>mm[i][1]>>mm[i][2]>>mm[i][3]>>mm[i][4];
}
solve();
int ans = INF;
for(int i=0;i<m;i++){
ans = min(dp[POW[m]-1][i],ans);
}
if(ans == INF){
cout<<-1<<endl;
}
else
cout<<ans<<endl;
}
return 0;
}