I want to replace special character*
to first Special character <b>
and second same special character to </b>
like that
我想将特殊字符*替换为第一个特殊字符,将第二个相同的特殊字符替换为
Example: This my original string
示例:这是我的原始字符串
Prime
*
Minister*
Digital India programme is an attempt to create a*
digitally empowered society*
, with financial inclusion contributing to a robust*
formal economy*
. The main idea behind this vision is not just connectivity, but about how to leverage that connectivity in enabling consumers, small businesses, traders and farmers to harness*
technology*
to maximise efficiency and*
productivity*
Prime *部长*数字印度计划旨在创建一个*数字授权社会*,金融包容有助于强大的*正规经济*。这一愿景背后的主要思想不仅仅是连通性,还包括如何利用这种连通性使消费者,小企业,贸易商和农民能够利用*技术*来最大限度地提高效率和*生产力*
I want to replace this special symbol like that
我想替换这样的特殊符号
Prime
<b>
Minister</b>
Digital India programme is an attempt to create a<b>
digitally empowered society</b>
, with financial inclusion contributing to a robust<b>
formal economy</b>
. The main idea behind this vision is not just connectivity, but about how to leverage that connectivity in enabling consumers, small businesses, traders and farmers to harness<b>
technology</b>
to maximise efficiency and<b>
productivity</b>
Prime 部长 数字印度计划旨在创建一个数字授权社会 ,金融包容性有助于强大的正规经济 。这一愿景背后的主要思想不仅仅是连通性,而是关于如何利用这种连通性使消费者,小企业,贸易商和农民能够利用技术 来最大限度地提高效率和生产力
Thanks in advance.
提前致谢。
1 个解决方案
#1
1
I think a regex is probably the wrong tool for this. You're probably better off writing a simple loop to check your requirement.
我认为正则表达式可能是错误的工具。你可能最好写一个简单的循环来检查你的要求。
Something like this :
像这样的东西:
int counter =0;
for(int i=0;i!=-1;) {
i=val.indexOf("*");
if(counter%2==0) {
val = val.replaceFirst("\\*","<b>");
} else {
val = val.replaceFirst("\\*","<\\\\b>");
}
counter++;
}
#1
1
I think a regex is probably the wrong tool for this. You're probably better off writing a simple loop to check your requirement.
我认为正则表达式可能是错误的工具。你可能最好写一个简单的循环来检查你的要求。
Something like this :
像这样的东西:
int counter =0;
for(int i=0;i!=-1;) {
i=val.indexOf("*");
if(counter%2==0) {
val = val.replaceFirst("\\*","<b>");
} else {
val = val.replaceFirst("\\*","<\\\\b>");
}
counter++;
}