I want to separate string and number in a file to get a specific number in bash script, such as:
我想在一个文件中分离字符串和数字，以获得bash脚本中的特定数字，例如:
Branches executed:75.38% of 1190
分支机构执行:75.38%的1190年
I want to only get number
我只想要数字
75.38
75.38
. I have try like the code below
。我试过如下代码
$new_value=value | sed -r 's/.*_([0-9]*)\..*/\1/g'
but it was incorrect and it was failed.
但这是错误的，而且失败了。
How should it works? Thank you before for your help.
应该是如何运作的吗?谢谢你之前的帮助。
3 个解决方案
#1
1
You can use the following regex to extract the first number in a line:
您可以使用以下regex提取一行中的第一个数字:
^[^0-9]*\([0-9.]*\).*$
Usage:
用法:
% echo 'Branches executed:75.38% of 1190' | sed 's/^[^0-9]*\([0-9.]*\).*$/\1/'
75.38
#2
1
Give this a try:
给这一个尝试:
value=$(sed "s/^Branches executed:\([0-9][.0-9]*[0-9]*\)%.*$/\1/" afile)
It is assumed that the line appears only once in afile.
假设该行只出现在一个文件中。
The value is stored in the value variable.
值存储在值变量中。
#3
0
There are several things here that we could improve. One is that you need to escape the parentheses in sed: \(...\)
这里有几个我们可以改进的地方。一个是您需要转义sed中的圆括号:\(…\)
Another one is that it would be good to have a full specification of the input strings as well as a good script that can help us to play with this.
另一个问题是，如果有一个完整的输入字符串规范，以及一个可以帮助我们处理这个问题的好脚本，那就更好了。
Anyway, this is my first attempt: Update: I added a little more bash around this regex so it'll be more easy to play with it:
无论如何，这是我的第一次尝试:Update:我在这个regex上添加了一些抨击，这样就更容易使用它:
value='Branches executed:75.38% of 1190'
new_value=`echo $value | sed -e 's/[^0-9]*\([0-9]*\.[0-9]*\).*/\1/g'`
echo $new_value
Update 2: as john pointed out, it will match only numbers that contain a decimal dot. We can fix it with an optional group: \(\.[0-9]\+\)?. An explanation for the optional group:
更新2:正如john指出的，它将只匹配包含小数点的数字。我们可以用一个可选的组来修复它:\(\.[0-9]\+\)?可选组的解释:
-
\(...\)is a group. - \(…\)是一组。
-
\(...\)?Is a group that appears zero or one times (mind the question mark). - \(…\)?是一个出现0或1次(注意问号)的组。
-
\.[0-9]\+is the pattern for a dot and one or more digits. - \。[0-9]\+是一个点和一个或多个数字的模式。
Putting all together:
把所有在一起:
value='Branches executed:75.38% of 1190'
new_value=`echo $value | sed -e 's/[^0-9]*\([0-9]\+\(\.[0-9]\+\)\?\).*/\1/g'`
echo $new_value
#1
1
You can use the following regex to extract the first number in a line:
您可以使用以下regex提取一行中的第一个数字:
^[^0-9]*\([0-9.]*\).*$
Usage:
用法:
% echo 'Branches executed:75.38% of 1190' | sed 's/^[^0-9]*\([0-9.]*\).*$/\1/'
75.38
#2
1
Give this a try:
给这一个尝试:
value=$(sed "s/^Branches executed:\([0-9][.0-9]*[0-9]*\)%.*$/\1/" afile)
It is assumed that the line appears only once in afile.
假设该行只出现在一个文件中。
The value is stored in the value variable.
值存储在值变量中。
#3
0
There are several things here that we could improve. One is that you need to escape the parentheses in sed: \(...\)
这里有几个我们可以改进的地方。一个是您需要转义sed中的圆括号:\(…\)
Another one is that it would be good to have a full specification of the input strings as well as a good script that can help us to play with this.
另一个问题是，如果有一个完整的输入字符串规范，以及一个可以帮助我们处理这个问题的好脚本，那就更好了。
Anyway, this is my first attempt: Update: I added a little more bash around this regex so it'll be more easy to play with it:
无论如何，这是我的第一次尝试:Update:我在这个regex上添加了一些抨击，这样就更容易使用它:
value='Branches executed:75.38% of 1190'
new_value=`echo $value | sed -e 's/[^0-9]*\([0-9]*\.[0-9]*\).*/\1/g'`
echo $new_value
Update 2: as john pointed out, it will match only numbers that contain a decimal dot. We can fix it with an optional group: \(\.[0-9]\+\)?. An explanation for the optional group:
更新2:正如john指出的，它将只匹配包含小数点的数字。我们可以用一个可选的组来修复它:\(\.[0-9]\+\)?可选组的解释:
-
\(...\)is a group. - \(…\)是一组。
-
\(...\)?Is a group that appears zero or one times (mind the question mark). - \(…\)?是一个出现0或1次(注意问号)的组。
-
\.[0-9]\+is the pattern for a dot and one or more digits. - \。[0-9]\+是一个点和一个或多个数字的模式。
Putting all together:
把所有在一起:
value='Branches executed:75.38% of 1190'
new_value=`echo $value | sed -e 's/[^0-9]*\([0-9]\+\(\.[0-9]\+\)\?\).*/\1/g'`
echo $new_value