搜索一个单词的字符串，并用不同的php链接替换该单词

Using PHP, how can i replace a word in a string with different links.

使用PHP，如何用不同的链接替换字符串中的单词。

I want to replace the word web development with different links in order

我想用不同的链接取代word web开发

This web development company is great. A good web development starts with...

这个web开发公司很棒。一个好的web开发始于……

like so

像这样

This web development company is great. A good web development starts with...

这个web开发公司很棒。一个好的web开发始于……

i have tried using str_ireplace but then both links lead to the same site.

我试过使用str_ireplace，但是两个链接都指向同一个站点。

Here is my code

这是我的代码

<?php

$text = 'This web development company is great. A good web development starts with...';


$replaced = str_ireplace(array('web development', 'web development'),array('<a href="http://google.com">web development</a>', '<a href="http://yahoo.com">web development</a>'), $text);

echo $replaced;

4 个解决方案

#1

I think you can use the preg_replace() function, as the following:

我认为可以使用preg_replace()函数，如下所示:

$pattern = '/(web development)(.*)(web development)/';
$replace = '<a href="http://google.com">web development</a>$2<a href="http://yahoo.com">web development</a>';
$result = preg_replace($pattern, $replace, $text);
echo $result;

Hope helps!

希望会有帮助!

#2

Try with regex like:

试着用正则表达式:

<?php
$text = 'This web development company is great. A good web development starts with...';

$regex = "/[^>]web development[^<]/i";
$replace = array(' <a href="http://google.com">web development</a> ', 
' <a href="http://yahoo.com">web development</a> ');
$count = 1;
$replaced = preg_replace(array($regex,$regex), $replace, $text, $count);

echo $replaced;

#3

Like in this topic you can do something like that (with preg_replace) :

就像在这个主题中，你可以做类似的事情(使用preg_replace):

$str = 'abc and abc'; 
$str = preg_replace('/abc/', 'google', $str, 1); 
$str = preg_replace('/abc/', 'yahoo', $str, 1);
echo $str;

It will display : "google and yahoo"

将显示:“谷歌和yahoo”

(I hope I understood your need)

(我希望我理解你的需要)

#4

I think you can do it with preg_replace.

我想你可以用preg_replace来实现。

Searches subject for matches to pattern and replaces them with replacement.

搜索与模式匹配的主题，并用替换替换它们。

You can set a limit to the times the word is going to be replaced.

你可以设置一个单词被替换的时间的限制。

limit: The maximum possible replacements for each pattern in each subject string. Defaults to -1 (no limit).

限制:每个主题字符串中每个模式的最大可能替换。默认为-1(没有限制)。

So, I think you can do a function that first, count the ocurrences of "Web Development" has your text, and then you execute:

所以，我认为你可以做一个函数，首先，数一下“Web开发”有你的文本，然后你执行:

$text = preg_replace("web development", "<a href='http://www.exemple.com'>web development</a>", $text, 1);

x times.

x乘以。

Remember the function preg_replace:

记住这个函数preg_replace:

preg_replace ( mixed $pattern , mixed $replacement , mixed $subject [, int $limit = -1 [, int &$count ]] )

See reference in the PHP Manual.

参见PHP手册中的参考。

#1