查找并替换文件中的字符串

I'm trying to find and replace a string in a folder of files.

我正在查找并替换文件文件夹中的一个字符串。

Could someone possibly help me?

有人能帮我一下吗?

My script is as follows:

我的剧本如下:

#!/bin/bash
OLD="This is a"
NEW="I am a"
DPATH="/home/user/test/*.txt"
BPATH="/home/user/test/backup/foo"
[ ! -d $BPATH ] && mkdir -p $BPATH || :
for f in $DPATH
do
  if [ -f $f -a -r $f ]; then
    /bin/cp -f $f $BPATH
    sed "s/$OLD/$NEW/g" "$f"
   else
    echo "Error: Cannot read $f"
  fi
done

Now this seems to find the string 'This is a' and replaces with 'I am a', but this only prints to screen.

现在这似乎找到了字符串“this is a”并用“I am a”替换，但这只会打印到屏幕上。

I need it to replace in the files themselves.

我需要它来替换文件本身。

Thanks

谢谢

4 个解决方案

#1

Use the -i option of sed to make the changes in place:

使用sed的-i选项进行更改:

sed -i "s/$OLD/$NEW/g" "$f"
    ^^

#2

The output goes to screen (stdout) because of the following:

输出进入屏幕(stdout)，原因如下:

sed "s/$OLD/$NEW/g" "$f"

Try redirecting to a file (the following redirects to a new files and then renames it to overwrite the original file):

尝试重定向到一个文件(以下是重定向到一个新文件，然后重命名它以覆盖原始文件):

sed "s/$OLD/$NEW/g" "$f" > "$f.new" && mv "$f.new" "$f"

#3

this is a snippet i use, it removes all stuff between APA and BEPA (across multiple lines, including removing APA, BEPA) in all files below current directory, exclude the .svn directory

这是我使用的一个片段，它在当前目录下的所有文件中删除APA和BEPA(跨多行，包括删除APA, BEPA)之间的所有内容，排除.svn目录

find . \! -path '*.svn*' -type f -exec sed -i -n '1h;1!H;${;g;s/APA[ \t\r\n]*BEPA//g;p}' {} \;

#4

Check this out

看看这个

http://cs.boisestate.edu/~amit/teaching/handouts/cs-unix/node130.html

http://cs.boisestate.edu/ amit /教学/救济/ cs-unix / node130.html

##########################################################
\#!/bin/sh

\# sed/changeword

prog=`basename $0`

case $# in
0|1) echo 'Usage:' $prog '<old string> <new string>'; exit 1;;
esac

old=$1
new=$2
for f in *
do
        if test "$f" != "$prog"

        then
            if test -f "$f"
            then
                sed "s/$old/$new/g" $f > $f.new
                mv $f $f.orig
                mv $f.new $f
                echo $f done
            fi
        fi
done

##############################################################

#1