Given an input file:
给定一个输入文件：
exception Error 1
exception Error 2
warning Error 123 (ignore)
warning Error 123 (ignore)
exception Error 3
I want to grep only lines which end with only Error 1 or Error 2, but not those which end with ignore. I don't want to use two grep commands by piping the output; I want to use only single grep command.
我只想grep只以Error 1或Error 2结尾的行，而不是那些以ignore结尾的行。我不想通过管道输出使用两个grep命令;我想只使用单个grep命令。
I tried something like grep "Error.." file though I am restricting it to two chars it still outputs ignore strings.
我尝试了类似grep“Error ..”文件的东西，虽然我将它限制为两个字符，它仍然输出忽略字符串。
1 个解决方案
#1
1
You can use end anchor in regex:
你可以在正则表达式中使用结束锚：
grep -E 'Error [12]$' file
exception Error 1
exception Error 2
or word boundary:
或字边界：
grep -E 'Error [12]\b' file
exception Error 1
exception Error 2
#1
1
You can use end anchor in regex:
你可以在正则表达式中使用结束锚：
grep -E 'Error [12]$' file
exception Error 1
exception Error 2
or word boundary:
或字边界：
grep -E 'Error [12]\b' file
exception Error 1
exception Error 2