如何grep双引号后跟一个字符串同时？

   [["QUALITY",**"AVM",200**,610865413,1,0,7,2,-1],[5,0,0,0,0,2],
   [0.998286,0,1,0,0],[0,0,0,0,0,0],["aq04rvtcmgff8"],
   [["QUALITY",**"AVM",200**,610865413,1,0,7,2,-1],[5,0,0,0,0,2],
   [0.998286,0,1,0,0],[0,0,0,0,0,0],["aq04rvtcmgff8"]
   [["QUALITY",**"AVM",200**,610865413,1,0,7,2,-1],[5,0,0,0,0,2],
   [0.998286,0,1,0,0],[0,0,0,0,0,0],["aq04rvtcmgff8"]
   [["QUALITY","AVM”,100,610865413,1,0,7,2,-1]

This is the log i have. I want to grep the pattern as follow:

这是我的日志。我想要模式如下：

**"AVM",200** - In the above log, how many time this pattern comes. Result should be **3**

I have tried:

我努力了：

**grep "\"AVM\",200" <file> | wc -l** --> but its not giving perfect result

1 个解决方案

#1

If there is single match per line, use -c option

如果每行有单个匹配项，请使用-c选项

grep -c '"AVM",200' log

If there are multiple matches, print one match per line and then count number of lines (depends on grep implementation, not all have -o option)

如果有多个匹配项，则每行打印一个匹配项，然后计算行数（取决于grep实现，不是所有都有-o选项）

grep -o '"AVM",200' log | wc -l

Or use GNU awk to set the search string as record separator and use number of records to get count

或者使用GNU awk将搜索字符串设置为记录分隔符，并使用记录数来计算

awk -v RS='"AVM",200' 'END{print NR-1}' log
# to handle empty input as well
awk -v RS='"AVM",200' 'END{print (NR>1?NR-1:0)}'

Or count number of occurrences per line

或计算每行的出现次数

awk -F'"AVM",200' 'NF{total += NF-1} END{print total+0}' log

#1