I would like get the last path segment in a URL:
我想获取URL中的最后一个路径段:
-
http://blabla/bla/wce/news.php
or - http://blabla/bla/wce/news.php或
http://blabla/blablabla/dut2a/news.php
- HTTP://blabla/blablabla/dut2a/news.php
For example, in these two URLs, I want to get the path segment: 'wce', and 'dut2a'.
例如,在这两个URL中,我想获得路径段:'wce'和'dut2a'。
I tried to use $_SERVER['REQUEST_URI']
, but I get the whole URL path.
我尝试使用$ _SERVER ['REQUEST_URI'],但我得到了整个URL路径。
9 个解决方案
#1
48
Try:
尝试:
$url = 'http://blabla/blablabla/dut2a/news.php';
$tokens = explode('/', $url);
echo $tokens[sizeof($tokens)-2];
Assuming $tokens
has at least 2 elements.
假设$令牌至少有2个元素。
#2
25
Try this:
尝试这个:
function getLastPathSegment($url) {
$path = parse_url($url, PHP_URL_PATH); // to get the path from a whole URL
$pathTrimmed = trim($path, '/'); // normalise with no leading or trailing slash
$pathTokens = explode('/', $pathTrimmed); // get segments delimited by a slash
if (substr($path, -1) !== '/') {
array_pop($pathTokens);
}
return end($pathTokens); // get the last segment
}
echo getLastPathSegment($_SERVER['REQUEST_URI']);
I've also tested it with a few URLs from the comments. I'm going to have to assume that all paths end with a slash, because I can not identify if /bob is a directory or a file. This will assume it is a file unless it has a trailing slash too.
我还用评论中的几个URL测试了它。我将不得不假设所有路径都以斜杠结尾,因为我无法识别/ bob是目录还是文件。这将假设它是一个文件,除非它也有一个尾部斜杠。
echo getLastPathSegment('http://server.com/bla/wce/news.php'); // wce
echo getLastPathSegment('http://server.com/bla/wce/'); // wce
echo getLastPathSegment('http://server.com/bla/wce'); // bla
#3
21
it is easy
这很容易
<?php
echo basename(dirname($url));
?>
#4
9
Try this:
尝试这个:
$parts = explode('/', 'your_url_here');
$last = end($parts);
#5
1
Another solution:
另一种方案:
$last_slash = strrpos('/', $url);
$last = substr($url, $last_slash);
1: getting the last slash position 2: getting the substring between the last slash and the end of string
1:获取最后一个斜杠位置2:获取最后一个斜杠和字符串结尾之间的子字符串
Look here: TEST
看这里:测试
#6
1
If you want to process an absolute URL, then you can use parse_url()
(it doesn't work with relative urls).
如果要处理绝对URL,则可以使用parse_url()(它不适用于相对URL)。
$url = 'http://aplicaciones.org/wp-content/uploads/2011/09/skypevideo-500x361.jpg?arg=value#anchor';
print_r(parse_url($url));
$url_path = parse_url($url, PHP_URL_PATH);
$parts = explode('/', $url_path);
$last = end($parts);
echo $last;
Full code example here: http://codepad.org/klqk5o29
完整的代码示例:http://codepad.org/klqk5o29
#8
0
$arr = explode("/", $uri);
#9
0
I wrote myself a little function to get the last dir/folder of an url. It only works with real/existing urls, not theoretical ones. In my case, that was always the case, so ...
我写了一个小函数来获取url的最后一个目录/文件夹。它只适用于实际/现有网址,而不是理论网址。就我而言,情况总是如此,所以......
function uf_getLastDir($sUrl)
{
$sPath = parse_url($sUrl, PHP_URL_PATH); // parse URL and return only path component
$aPath = explode('/', trim($sPath, '/')); // remove surrounding "/" and return parts into array
end($aPath); // last element of array
if (is_dir($sPath)) // if path points to dir
return current($aPath); // return last element of array
if (is_file($sPath)) // if path points to file
return prev($aPath); // return second to last element of array
return false; // or return false
}
Works for me! Enjoy! And kudos to the previous answers!!!
适合我!请享用!并赞赏以前的答案!!!
#1
48
Try:
尝试:
$url = 'http://blabla/blablabla/dut2a/news.php';
$tokens = explode('/', $url);
echo $tokens[sizeof($tokens)-2];
Assuming $tokens
has at least 2 elements.
假设$令牌至少有2个元素。
#2
25
Try this:
尝试这个:
function getLastPathSegment($url) {
$path = parse_url($url, PHP_URL_PATH); // to get the path from a whole URL
$pathTrimmed = trim($path, '/'); // normalise with no leading or trailing slash
$pathTokens = explode('/', $pathTrimmed); // get segments delimited by a slash
if (substr($path, -1) !== '/') {
array_pop($pathTokens);
}
return end($pathTokens); // get the last segment
}
echo getLastPathSegment($_SERVER['REQUEST_URI']);
I've also tested it with a few URLs from the comments. I'm going to have to assume that all paths end with a slash, because I can not identify if /bob is a directory or a file. This will assume it is a file unless it has a trailing slash too.
我还用评论中的几个URL测试了它。我将不得不假设所有路径都以斜杠结尾,因为我无法识别/ bob是目录还是文件。这将假设它是一个文件,除非它也有一个尾部斜杠。
echo getLastPathSegment('http://server.com/bla/wce/news.php'); // wce
echo getLastPathSegment('http://server.com/bla/wce/'); // wce
echo getLastPathSegment('http://server.com/bla/wce'); // bla
#3
21
it is easy
这很容易
<?php
echo basename(dirname($url));
?>
#4
9
Try this:
尝试这个:
$parts = explode('/', 'your_url_here');
$last = end($parts);
#5
1
Another solution:
另一种方案:
$last_slash = strrpos('/', $url);
$last = substr($url, $last_slash);
1: getting the last slash position 2: getting the substring between the last slash and the end of string
1:获取最后一个斜杠位置2:获取最后一个斜杠和字符串结尾之间的子字符串
Look here: TEST
看这里:测试
#6
1
If you want to process an absolute URL, then you can use parse_url()
(it doesn't work with relative urls).
如果要处理绝对URL,则可以使用parse_url()(它不适用于相对URL)。
$url = 'http://aplicaciones.org/wp-content/uploads/2011/09/skypevideo-500x361.jpg?arg=value#anchor';
print_r(parse_url($url));
$url_path = parse_url($url, PHP_URL_PATH);
$parts = explode('/', $url_path);
$last = end($parts);
echo $last;
Full code example here: http://codepad.org/klqk5o29
完整的代码示例:http://codepad.org/klqk5o29
#7
#8
0
$arr = explode("/", $uri);
#9
0
I wrote myself a little function to get the last dir/folder of an url. It only works with real/existing urls, not theoretical ones. In my case, that was always the case, so ...
我写了一个小函数来获取url的最后一个目录/文件夹。它只适用于实际/现有网址,而不是理论网址。就我而言,情况总是如此,所以......
function uf_getLastDir($sUrl)
{
$sPath = parse_url($sUrl, PHP_URL_PATH); // parse URL and return only path component
$aPath = explode('/', trim($sPath, '/')); // remove surrounding "/" and return parts into array
end($aPath); // last element of array
if (is_dir($sPath)) // if path points to dir
return current($aPath); // return last element of array
if (is_file($sPath)) // if path points to file
return prev($aPath); // return second to last element of array
return false; // or return false
}
Works for me! Enjoy! And kudos to the previous answers!!!
适合我!请享用!并赞赏以前的答案!!!