Wondering how to substring the last two characters quickly in Java?
想知道如何在Java中快速子字符串最后两个字符?
4 个解决方案
#1
98
The existing answers will fail if the string is empty or only has one character. Options:
如果字符串为空或只有一个字符,则现有答案将失败。选项:
String substring = str.length() > 2 ? str.substring(str.length() - 2) : str;
or
要么
String substring = str.substring(Math.max(str.length() - 2, 0));
That's assuming that str
is non-null, and that if there are fewer than 2 characters, you just want the original string.
这是假设str是非空的,如果少于2个字符,你只需要原始字符串。
#2
14
theString.substring(theString.length() - 2)
#3
12
String value = "somestring";
String lastTwo = null;
if (value != null && value.length() >= 2) {
lastTwo = value.substring(value.length() - 2);
}
#1
98
The existing answers will fail if the string is empty or only has one character. Options:
如果字符串为空或只有一个字符,则现有答案将失败。选项:
String substring = str.length() > 2 ? str.substring(str.length() - 2) : str;
or
要么
String substring = str.substring(Math.max(str.length() - 2, 0));
That's assuming that str
is non-null, and that if there are fewer than 2 characters, you just want the original string.
这是假设str是非空的,如果少于2个字符,你只需要原始字符串。
#2
14
theString.substring(theString.length() - 2)
#3
12
String value = "somestring";
String lastTwo = null;
if (value != null && value.length() >= 2) {
lastTwo = value.substring(value.length() - 2);
}