删除字符串的最后两个字符[复制]

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How to remove the last character from a string? 24 answers

如何从字符串中删除最后一个字符? 24个答案

How can I delete the last two characters 05 of the simple string?

如何删除简单字符串的最后两个字符05?

Simple:

"apple car 05"

Code

String[] lineSplitted = line.split(":");
String stopName = lineSplitted[0];
String stop =   stopName.substring(0, stopName.length() - 1);
String stopEnd = stopName.substring(0, stop.length() - 1);

orginal line before splitting ":"

分裂前的原始线“:”

apple car 04:48 05:18 05:46 06:16 06:46 07:16 07:46 16:46 17:16 17:46 18:16 18:46 19:16

7 个解决方案

#1

Subtract -2 or -3 basis of removing last space also.

减去最后一个空格的-2或-3基础。

 public static void main(String[] args) {
        String s = "apple car 05";
        System.out.println(s.substring(0, s.length() - 2));
    }

Output

apple car

#2

Use String.substring(beginIndex, endIndex)

使用String.substring(beginIndex,endIndex)

str.substring(0, str.length() - 2);

The substring begins at the specified beginIndex and extends to the character at index (endIndex - 1)

子字符串从指定的beginIndex开始并扩展到index处的字符(endIndex - 1)

#3

You may use the following method to remove last n character -

您可以使用以下方法删除最后n个字符 -

public String removeLast(String s, int n) {
    if (null != s && !s.isEmpty()) {
        s = s.substring(0, s.length()-n);
    }
    return s;
}

#4

You can use substring function:

你可以使用substring函数:

s.substring(0,s.length() - 2));

With the first 0, you say to substring that it has to start in the first character of your string and with the s.length() - 2 that it has to finish 2 characters before the String ends.

对于第一个0,你要说子串必须从你的字符串的第一个字符开始,并且使用s.length() - 2,它必须在字符串结束之前完成2个字符。

For more information about substring function you can see here:

有关子字符串函数的更多信息,请参见此处:

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

#5

You may also try the following code with exception handling. Here you have a method removeLast(String s, int n) (it is actually an modified version of masud.m's answer). You have to provide the String s and how many char you want to remove from the last to this removeLast(String s, int n) function. If the number of chars have to remove from the last is greater than the given String length then it throws a StringIndexOutOfBoundException with a custom message -

您还可以尝试使用以下代码进行异常处理。这里有一个方法removeLast(String s,int n)(它实际上是masud.m的答案的修改版本)。您必须提供String以及要从最后一个removeLast(String s,int n)函数中删除的char数。如果必须从最后删除的字符数大于给定的字符串长度,则它会抛出带有自定义消息的StringIndexOutOfBoundException -

public String removeLast(String s, int n) throws StringIndexOutOfBoundsException{

        int strLength = s.length();

        if(n>strLength){
            throw new StringIndexOutOfBoundsException("Number of character to remove from end is greater than the length of the string");
        }

        else if(null!=s && !s.isEmpty()){

            s = s.substring(0, s.length()-n);
        }

        return s;

    }

#6

It was almost correct just change your last line like:

这几乎是正确的,只需改变你的最后一行:

String stopEnd = stop.substring(0, stop.length() - 1); //replace stopName with stop.

you can replace your last two lines;

你可以替换你的最后两行;

String stopEnd =   stopName.substring(0, stopName.length() - 2);

#7

An alternative solution would be to use some sort of regex:

另一种解决方案是使用某种正则表达式:

for example:

    String s = "apple car 04:48 05:18 05:46 06:16 06:46 07:16 07:46 16:46 17:16 17:46 18:16 18:46 19:16";
    String results=  s.replaceAll("[0-9]", "").replaceAll(" :", ""); //first removing all the numbers then remove space followed by :
    System.out.println(results); // output 9
    System.out.println(results.length());// output "apple car"

#1