IntelliSense：对象具有与成员函数不兼容的类型限定符

I have a class called Person:

我有一个名为Person的类:

class Person {
    string name;
    long score;
public:
    Person(string name="", long score=0);
    void setName(string name);
    void setScore(long score);
    string getName();
    long getScore();
};

In another class, I have this method:

在另一个类中,我有这个方法:

void print() const {
     for (int i=0; i< nPlayers; i++)
        cout << "#" << i << ": " << people[i].getScore()//people is an array of person objects
    << " " << people[i].getName() << endl;
}

This is the declaration of people:

这是人们的宣言:

    static const int size=8; 
    Person people[size]; 

When I try to compile it I get this error:

当我尝试编译它时,我收到此错误:

IntelliSense: the object has type qualifiers that are not compatible with the member function

with red lines under the the 2 people[i] in the print method

打印方法中2人[i]下的红线

What am I doing wrong?

我究竟做错了什么?

1 个解决方案

#1

getName is not const, getScore is not const, but print is. Make the first two const like print. You cannot call a non-const method with a const object. Since your Person objects are direct members of your other class and since you are in a const method they are considered const.

getName不是const,getScore不是const,而是print。使前两个const像print一样。您不能使用const对象调用非const方法。由于您的Person对象是您的其他类的直接成员,并且因为您使用const方法,所以它们被视为const。

In general you should consider every method you write and declare it const if that's what it is. Simple getters like getScore and getName should always be const.

通常,您应该考虑您编写的每个方法,并将其声明为const,如果它是这样的话。像getScore和getName这样的简单getter应该始终是const。