What I want to know is the most code efficient way to convert (in swift 2):
我想知道的是转换代码最有效的方法（在swift 2中）：
- Decimal to Binary
- 十进制到二进制
- Binary to Decimal
- 二进制到十进制
- Decimal to Hexadecimal
- 十进制到十六进制
- Hexadecimal to Decimal
- 十六进制到十进制
- Binary to Hexadecimal
- 二进制到十六进制
- Hexadecimal to Binary
- 十六进制到二进制
I already have a rudimentary and long-winded way of achieving this, but I would like to find out a very efficient way of doing it.
我已经有了一个基本的，冗长的方法来实现这一目标，但我想找到一种非常有效的方法。
Sorry if the question is a bit long...
对不起，如果问题有点长......
1 个解决方案
#1
35
Both String and Int have constructors which take a radix (base). Combining those, you can achieve all of the conversions:
String和Int都有构造函数，它们采用基数（基数）。结合这些，您可以实现所有转换：
// Decimal to binary
let d1 = 21
let b1 = String(d1, radix: 2)
print(b1) // "10101"
// Binary to decimal
let b2 = "10110"
let d2 = Int(b2, radix: 2)!
print(d2) // 22
// Decimal to hexadecimal
let d3 = 61
let h1 = String(d3, radix: 16)
print(h1) // "3d"
// Hexadecimal to decimal
let h2 = "a3"
let d4 = Int(h2, radix: 16)!
print(d4) // 163
// Binary to hexadecimal
let b3 = "10101011"
let h3 = String(Int(b3, radix: 2)!, radix: 16)
print(h3) // "ab"
// Hexadecimal to binary
let h4 = "face"
let b4 = String(Int(h4, radix: 16)!, radix: 2)
print(b4) // "1111101011001110"
#1
35
Both String and Int have constructors which take a radix (base). Combining those, you can achieve all of the conversions:
String和Int都有构造函数，它们采用基数（基数）。结合这些，您可以实现所有转换：
// Decimal to binary
let d1 = 21
let b1 = String(d1, radix: 2)
print(b1) // "10101"
// Binary to decimal
let b2 = "10110"
let d2 = Int(b2, radix: 2)!
print(d2) // 22
// Decimal to hexadecimal
let d3 = 61
let h1 = String(d3, radix: 16)
print(h1) // "3d"
// Hexadecimal to decimal
let h2 = "a3"
let d4 = Int(h2, radix: 16)!
print(d4) // 163
// Binary to hexadecimal
let b3 = "10101011"
let h3 = String(Int(b3, radix: 2)!, radix: 16)
print(h3) // "ab"
// Hexadecimal to binary
let h4 = "face"
let b4 = String(Int(h4, radix: 16)!, radix: 2)
print(b4) // "1111101011001110"