从字符串中删除重复的字符

How can I remove duplicate characters from a string using Python? For example, let's say I have a string:

如何使用Python从字符串中删除重复的字符?例如,假设我有一个字符串:

foo = 'mppmt'

How can I make the string:

我该如何制作字符串:

foo = 'mpt'

NOTE: Order is not important

注意:订单并不重要

8 个解决方案

#1

If order does not matter, you can use

如果订单无关紧要,您可以使用

"".join(set(foo))

set() will create a set of unique letters in the string, and "".join() will join the letters back to a string in arbitrary order.

set()将在字符串中创建一组唯一字母,“”。join()将以任意顺序将字母连接回字符串。

If order does matter, you can use collections.OrderedDict in Python 2.7:

如果顺序很重要,可以在Python 2.7中使用collections.OrderedDict:

from collections import OrderedDict
foo = "mppmt"
print "".join(OrderedDict.fromkeys(foo))

printing

mpt

#2

If order does matter, how about:

如果订单确实重要,那么:

>>> foo = 'mppmt'
>>> ''.join(sorted(set(foo), key=foo.index))
'mpt'

#3

If order is not the matter:

如果订单不是问题:

>>> foo='mppmt'
>>> ''.join(set(foo))
'pmt'

To keep the order:

保持订单:

>>> foo='mppmt'
>>> ''.join([j for i,j in enumerate(foo) if j not in foo[:i]])
'mpt'

#4

If order is important,

如果订单很重要,

seen = set()
result = []
for c in foo:
    if c not in seen:
        result.append(c)
        seen.add(c)
result = ''.join(result)

Or to do it without sets:

或者没有套装:

result = []
for c in foo:
    if c not in result:
        result.append(c)
result = ''.join(result)

#5

As was mentioned "".join(set(foo)) and collections.OrderedDict will do. A added foo = foo.lower() in case the string has upper and lower case characters and you need to remove ALL duplicates no matter if they're upper or lower characters.

正如前面提到的那样。“。join(set(foo))和collections.OrderedDict会做。添加foo = foo.lower()以防字符串具有大写和小写字符,并且您需要删除所有重复项,无论它们是大写还是小写字符。

from collections import OrderedDict
foo = "EugeneEhGhsnaWW"
foo = foo.lower()
print "".join(OrderedDict.fromkeys(foo))

prints eugnhsaw

#6

#We can do it simply by using Regex libs of python.

#Check code and apply in your Program:

#Input= 'pppmm'

import re as reg
s='ppppmm'
pattern=reg.compile(r"(.)\1{1,}",reg.DOTALL)
string=pattern.sub(r"\1",s)
print(string)

#Output: pm

#7

Create a list in Python and also a set which doesn't allow any duplicates. Solution1 :

在Python中创建一个列表,也是一个不允许任何重复的集合。解决方案1:

def fix(string):
    s = set()
    list = []
    for ch in string:
        if ch not in s:
            s.add(ch)
            list.append(ch)

    return ''.join(list)        

string = "Protiijaayiiii"
print(fix(string))

Method 2 :

方法2:

s = "Protijayi"

aa = [ ch  for i, ch in enumerate(s) if ch not in s[:i]]
print(''.join(aa))

#8

def dupe(str1):
    s=set(str1)

    return "".join(s)
str1='geeksforgeeks'
a=dupe(str1)
print(a)

works well if order is not important.

如果订单不重要,效果很好。

#1