如何将模型实例分配给django中的类属性

thanks first!
I met a problem when using custom class,here is the code:
class definition:

先谢谢！我在使用自定义类时遇到了问题，这里是代码：类定义：

class BaseCompetition:
    def __init__(self, company):
        self.company = company
class SingleLeagueCompetition(Competition):
    def __init__(self, company):
    BaseCompetition.__init__(self,company)

when using it,like this:

使用它时，像这样：

test_company = Company.objects.get(id=1)
sample_single = SingleLeagueCompetition(test_company)

'Company' is a model.
But I got a error when executing the code,like this:
I just don't know what's wrong...

'公司'是一个典范。但是在执行代码时我遇到了错误，就像这样：我只是不知道什么是错的......

Traceback (most recent call last):
File "/Users/littlep/myWorks/python-works/sports_with_zeal/swz/dao.py", line 32, in __init__
self.company = company
File "/Users/littlep/.pythonbrew/pythons/Python-3.4.3/lib/python3.4/site-packages/django/db/models/fields/related.py", line 639, in __set__
if instance._state.db is None:
AttributeError: 'SingleLeagueCompetition' object has no attribute '_state'

Thanks again!

再次感谢！

1 个解决方案

#1

Your SingleLeagueCompetition class should inherit from BaseCompetition, like this:

您的SingleLeagueCompetition类应该从BaseCompetition继承，如下所示：

class BaseCompetition:
    def __init__(self, company):
        self.company = company
class SingleLeagueCompetition(BaseCompetition):
    def __init__(self, company):
        super().__init__(company)

also instead of call constructor by using parent class BaseCompetition._init_ you can use super to bind it in child.

通过使用父类BaseCompetition._init_而不是调用构造函数，您可以使用super将其绑定到child中。

More reference consult: https://docs.python.org/3.4/library/functions.html#super

更多参考咨询：https：//docs.python.org/3.4/library/functions.html#super

#1