如何获得模型的名称或Django对象的内容类型?

Let's say I am in the save code. How can I obtain the model's name or the content type of the object, and use it?

假设我在保存代码中。如何获取模型的名称或对象的内容类型并使用它?

from django.db import models

class Foo(models.Model):
    ...
    def save(self):
        I am here....I want to obtain the model_name or the content type of the object

This code works, but I have to know the model_name:

这个代码可以工作，但是我必须知道model_name:

import django.db.models
from django.contrib.contenttypes.models import ContentType

content_type = ContentType.objects.get(model=model_name)
model = content_type.model_class()

1 个解决方案

#1

You can get the model name from the object like this:

可以从对象中获取模型名，如下所示:

self.__class__.__name__

If you prefer the content type, you should be able to get that like this:

如果您喜欢内容类型，您应该能够得到如下内容:

ContentType.objects.get_for_model(self)

#1