Here's a prop.test function:
这是一个道具。测试功能:
baby.prop.test = function (x, n, p, conf.level = 0.95) {
# ...
return(prop.test(x,n,p,conf.level))
#baby.prop.test$statistic
}
# test case
baby.prop = baby.prop.test(72, 100, .7, conf.level=.99)
stopifnot(isTRUE(all.equal(as.numeric(baby.prop$statistic), .43643578)))
stopifnot(isTRUE(all.equal(as.numeric(baby.prop$p.value), .66252058)))
Here is the error:
这是错误:
Error in match.arg(alternative) :
'arg' must be NULL or a character vector
Any idea what's wrong?
知道有什么问题吗?
1 个解决方案
#1
4
According to formals(prop.test)
or ?prop.test
the fourth argument is called alternative
and has to be a character of c("two.sided", "less", "greater")
. Your fourth element is conf.level
(which is the fifth of prop.test
, the order matters). To "ignore" the order of arguments you have to name your arguments (at least the conf.level
):
根据形式(prop.test)或?道具。测试第四个参数称为alternative,必须是c的字符(“two”。站”、“少”、“更大的”)。第四个元素是conf.level(这是第五个元素)。测试,订单问题)。要“忽略”论点的顺序,你必须给你的论点起个名字(至少是承认的程度):
prop.test(x, n, p, conf.level=conf.level)
#1
4
According to formals(prop.test)
or ?prop.test
the fourth argument is called alternative
and has to be a character of c("two.sided", "less", "greater")
. Your fourth element is conf.level
(which is the fifth of prop.test
, the order matters). To "ignore" the order of arguments you have to name your arguments (at least the conf.level
):
根据形式(prop.test)或?道具。测试第四个参数称为alternative,必须是c的字符(“two”。站”、“少”、“更大的”)。第四个元素是conf.level(这是第五个元素)。测试,订单问题)。要“忽略”论点的顺序,你必须给你的论点起个名字(至少是承认的程度):
prop.test(x, n, p, conf.level=conf.level)