如何使用Newtonsoft解析我在c#(4.0)中的json字符串。Json包吗?

时间:2022-03-09 17:03:53

I am new to JSON.In my asp.net application i want to parse the json string.So, i have used Newtonsoft.Json package for reading and writing json data.Now, i can able to parse the simple json data.But now i have received some complex json data for parsing.So, i little bit struck on it.

我对JSON很陌生。在我的asp.net应用程序中,我想解析json字符串。我用了Newtonsoft。用于读取和写入Json数据的Json包。现在,我可以解析简单的json数据了。但是现在我收到了一些复杂的json数据用于解析。所以,我有点吃惊。

This is JSON Data:

这是JSON数据:

{
    quizlist: [
     {
            QUIZ: {
                'QPROP': [
                    {
                        'name': 'FB',
                        'intro': '',
                        'timeopen': '1347871440',
                        'timeclose': '1355733840',
                        'timelimit': '0',
                        'noofques': '5',
                        'QUESTION': {
                            'QUEPROP': [
                                {
                                    'questiontext': 'Scienceisbasedont',
                                    'penalty': '0.3333333',
                                    'qtype': 'shortanswer',
                                    'answer': 'cause-and-effect',
                                    'mark'  : '5',
                                    'hint': ''
                                },
                                {
                                    'questiontext': 'otherscientistsevaluateit',
                                    'penalty': '0.3333333',
                                    'qtype': 'shortanswer',
                                    'answer': 'Peerreview',
                                    'mark'  : '5',
                                    'hint': ''
                                },
                                {
                                    'questiontext': 'Watchingavariety',
                                    'penalty': '0.3333333',
                                    'qtype': 'shortanswer',
                                    'answer': 'inductive',
                                    'mark'  : '5',
                                    'hint': ''
                                },
                                {
                                    'questiontext': 'coveriesorideas',
                                    'penalty': '0.3333333',
                                    'qtype': 'shortanswer',
                                    'answer': 'paradigmshift',
                                    'mark'  : '5',
                                    'hint': ''
                                },
                                {
                                    'questiontext': 'proportions',
                                    'penalty': '0.3333333',
                                    'qtype': 'shortanswer',
                                    'answer': 'fixed',
                                    'mark'  : '5',
                                    'hint': ''
                                }
                            ]
                        }
                    }
                ]
            }
        }
     ]
}

This is my C# Code :

这是我的c#代码:

dynamic dynObj = JsonConvert.DeserializeObject(jsonString);

            foreach (var data in dynObj.quizlist)
            {
                foreach (var data1 in data.QUIZ.QPROP)
                {
                    Response.Write("Name" + ":" + data1.name + "<br>");
                    Response.Write("Intro" + ":" + data1.intro + "<br>");
                    Response.Write("Timeopen" + ":" + data1.timeopen + "<br>");
                    Response.Write("Timeclose" + ":" + data1.timeclose + "<br>");
                    Response.Write("Timelimit" + ":" + data1.timelimit + "<br>");
                    Response.Write("Noofques" + ":" + data1.noofques + "<br>");
                }
              }

I can able to parse until noofques object in QPROP array objects.Now have to parse data.QUIZ.QPROP.QUESTION.QUEPROP array objects also...

我可以解析到QPROP数组对象中的noofques。现在必须解析data.QUIZ.QPROP.QUESTION。QUEPROP数组对象还……

But i failed to parse fully...

但我没能完全解析……

Please guide me to get out of this issue...

请引导我离开这个问题……

4 个解决方案

#1


14  

foreach (var data in dynObj.quizlist)
{
    foreach (var data1 in data.QUIZ.QPROP)
    {
        Response.Write("Name" + ":" + data1.name + "<br>");
        Response.Write("Intro" + ":" + data1.intro + "<br>");
        Response.Write("Timeopen" + ":" + data1.timeopen + "<br>");
        Response.Write("Timeclose" + ":" + data1.timeclose + "<br>");
        Response.Write("Timelimit" + ":" + data1.timelimit + "<br>");
        Response.Write("Noofques" + ":" + data1.noofques + "<br>");

        foreach (var queprop in data1.QUESTION.QUEPROP)
        {
            Response.Write("Questiontext" + ":" + queprop.questiontext  + "<br>");
            Response.Write("Mark" + ":" + queprop.mark  + "<br>");
        }
    }
}

#2


9  

You can use this tool to create appropriate c# classes:

您可以使用此工具创建适当的c#类:

http://jsonclassgenerator.codeplex.com/

http://jsonclassgenerator.codeplex.com/

and when you will have classes created you can simply convert string to object:

当你要创建类时,你可以简单地将字符串转换为对象:

    public static T ParseJsonObject<T>(string json) where T : class, new()
    {
        JObject jobject = JObject.Parse(json);
        return JsonConvert.DeserializeObject<T>(jobject.ToString());
    }

Here that classes: http://ge.tt/2KGtbPT/v/0?c

这类:http://ge.tt/2KGtbPT/v/0?c

Just fix namespaces.

只是解决命名空间。

Regards

问候

#3


5  

You could create your own class of type Quiz and then deserialize with strong type:

你可以创建自己的类型测试类,然后用强类型反序列化:

Example:

例子:

quizresult = JsonConvert.DeserializeObject<Quiz>(args.Message,
                 new JsonSerializerSettings
                 {
                     Error = delegate(object sender1, ErrorEventArgs args1)
                     {
                         errors.Add(args1.ErrorContext.Error.Message);
                         args1.ErrorContext.Handled = true;
                     }
                 });

And you could also apply a schema validation.

您还可以应用模式验证。

http://james.newtonking.com/projects/json/help/index.html

http://james.newtonking.com/projects/json/help/index.html

#4


3  

This is a simple example of JSON parsing by taking example of google map API. This will return City name of given zip code.

这是一个简单的JSON解析示例,以谷歌map API为例。这将返回给定邮政编码的城市名称。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using Newtonsoft.Json;
using System.Net;

namespace WebApplication1
{
    public partial class WebForm1 : System.Web.UI.Page
    {
        WebClient client = new WebClient();
        string jsonstring;
        protected void Page_Load(object sender, EventArgs e)
        {

        }

        protected void Button1_Click(object sender, EventArgs e)
        {
            jsonstring = client.DownloadString("http://maps.googleapis.com/maps/api/geocode/json?address="+txtzip.Text.Trim());
            dynamic dynObj = JsonConvert.DeserializeObject(jsonstring);

            Response.Write(dynObj.results[0].address_components[1].long_name);
        }
    }
}

#1


14  

foreach (var data in dynObj.quizlist)
{
    foreach (var data1 in data.QUIZ.QPROP)
    {
        Response.Write("Name" + ":" + data1.name + "<br>");
        Response.Write("Intro" + ":" + data1.intro + "<br>");
        Response.Write("Timeopen" + ":" + data1.timeopen + "<br>");
        Response.Write("Timeclose" + ":" + data1.timeclose + "<br>");
        Response.Write("Timelimit" + ":" + data1.timelimit + "<br>");
        Response.Write("Noofques" + ":" + data1.noofques + "<br>");

        foreach (var queprop in data1.QUESTION.QUEPROP)
        {
            Response.Write("Questiontext" + ":" + queprop.questiontext  + "<br>");
            Response.Write("Mark" + ":" + queprop.mark  + "<br>");
        }
    }
}

#2


9  

You can use this tool to create appropriate c# classes:

您可以使用此工具创建适当的c#类:

http://jsonclassgenerator.codeplex.com/

http://jsonclassgenerator.codeplex.com/

and when you will have classes created you can simply convert string to object:

当你要创建类时,你可以简单地将字符串转换为对象:

    public static T ParseJsonObject<T>(string json) where T : class, new()
    {
        JObject jobject = JObject.Parse(json);
        return JsonConvert.DeserializeObject<T>(jobject.ToString());
    }

Here that classes: http://ge.tt/2KGtbPT/v/0?c

这类:http://ge.tt/2KGtbPT/v/0?c

Just fix namespaces.

只是解决命名空间。

Regards

问候

#3


5  

You could create your own class of type Quiz and then deserialize with strong type:

你可以创建自己的类型测试类,然后用强类型反序列化:

Example:

例子:

quizresult = JsonConvert.DeserializeObject<Quiz>(args.Message,
                 new JsonSerializerSettings
                 {
                     Error = delegate(object sender1, ErrorEventArgs args1)
                     {
                         errors.Add(args1.ErrorContext.Error.Message);
                         args1.ErrorContext.Handled = true;
                     }
                 });

And you could also apply a schema validation.

您还可以应用模式验证。

http://james.newtonking.com/projects/json/help/index.html

http://james.newtonking.com/projects/json/help/index.html

#4


3  

This is a simple example of JSON parsing by taking example of google map API. This will return City name of given zip code.

这是一个简单的JSON解析示例,以谷歌map API为例。这将返回给定邮政编码的城市名称。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using Newtonsoft.Json;
using System.Net;

namespace WebApplication1
{
    public partial class WebForm1 : System.Web.UI.Page
    {
        WebClient client = new WebClient();
        string jsonstring;
        protected void Page_Load(object sender, EventArgs e)
        {

        }

        protected void Button1_Click(object sender, EventArgs e)
        {
            jsonstring = client.DownloadString("http://maps.googleapis.com/maps/api/geocode/json?address="+txtzip.Text.Trim());
            dynamic dynObj = JsonConvert.DeserializeObject(jsonstring);

            Response.Write(dynObj.results[0].address_components[1].long_name);
        }
    }
}