计算SQL Server中每小时的行数，并显示完整的日期时间值

How can I count the number of rows per hour in SQL Server with full date-time as result.

如何计算SQL Server中每小时的行数，并将结果作为完整日期时间。

I've already tried this, but it returns only the hours

我已经试过了，但它只返回了几个小时

SELECT DATEPART(HOUR,TimeStamp), Count(*)
FROM [TEST].[dbo].[data]
GROUP BY DATEPART(HOUR,TimeStamp)
ORDER BY DATEPART(HOUR,TimeStamp)

Now the result is:

结果是：

Hour   Occurrence 
----   ----------
10     2157
11     60740
12     66189
13     77096
14     90039

But I need this:

但我需要这个：

Timestamp               Occurrence
-------------------     ----------
2013-12-21 10:00:00     2157
2013-12-21 11:00:00     60740
2013-12-21 12:00:00     66189
2013-12-21 13:00:00     77096
2013-12-21 14:00:00     90039
2013-12-22 09:00:00     84838
2013-12-22 10:00:00     64238

1 个解决方案

#1

You actually need to round the TimeStamp to the hour. In SQL Server, this is a bit ugly, but easy to do:

你实际上需要将TimeStamp四舍五入到小时。在SQL Server中，这有点难看，但很容易做到：

SELECT dateadd(hour, datediff(hour, 0, TimeStamp), 0) as TimeStampHour, Count(*)
FROM [TEST].[dbo].[data]
GROUP BY dateadd(hour, datediff(hour, 0, TimeStamp), 0)
ORDER BY dateadd(hour, datediff(hour, 0, TimeStamp), 0);