从日期时间字段中删除时间

In a field the date and time is set like "10/9/2014 7:43 PM".

在字段中，日期和时间设置为“10/9/2014 7:43 PM”。

I want to remove the time and need only the date so that I compare it with today's date. I.e., I want only "10/9/2014".

我想删除时间，只需要日期，以便将其与今天的日期进行比较。即，我只想要“10/9/2014”。

Could anyone suggest how to do it?

谁能建议怎么做？

3 个解决方案

#1

Is it a string or a DateTime object?

它是字符串还是DateTime对象？

If it's a DateTime object, just use to_date that will convert it to date:

如果它是一个DateTime对象，只需使用to_date将其转换为日期：

 myDate.to_date

If it's a String, just split it and get the first part:

如果它是一个字符串，只需拆分它并得到第一部分：

"10/9/2014 7:43 PM".split(' ').first
=> "10/9/2014"

#2

I'd do

我会做

require 'date'
date = Date.parse  "10/9/2014 7:43 PM"
# => #<Date: 2014-09-10 ((2456911j,0s,0n),+0s,2299161j)>
date.to_s # => "2014-09-10"

Another way using Date::strptime

另一种使用Date :: strptime的方法

date = Date.strptime("10/9/2014 7:43 PM", "%d/%m/%Y %l:%M %p")
# => #<Date: 2014-09-10 ((2456911j,0s,0n),+0s,2299161j)>
date.to_s # => "2014-09-10"

#3

You can format the date:

您可以格式化日期：

d = DateTime.new(2014, 10, 9, 7, 43, 0)
d.strftime("%m/%d/%Y") -> Gives "10/09/2014

or you can do d.strftime("%D")

或者你可以做d.strftime（“％D”）

#1