This question already has an answer here:
这个问题在这里已有答案:
- Displaying a number in Indian format using Javascript 12 answers
使用Javascript 12答案以印度格式显示数字
I used the following regex
我使用了以下正则表达式
var x=32423332.343;
var res= x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
which gives an output of 32,423,332.343
它的输出为32,423,332.343
How do I modify this regex (shortest way) to get the following output
如何修改此正则表达式(最短路径)以获得以下输出
3,24,23,332.343
1 个解决方案
#1
1
Well, if you want that, you can modify your regex a bit:
好吧,如果你想要,你可以修改你的正则表达式:
\B(?=(?:\d{2})*\d{3}(?!\d))
(?:\d{2})* will match even number of digits before the final \d{3}.
(?:\ d {2})*将匹配最终\ d {3}之前的偶数位数。
For PCRE engine, one that can handle integers and floating, with g enabled.
对于PCRE引擎,可以处理整数和浮动,启用g。
\G\d{1,2}\K\B(?=(?:\d{2})*\d{3}(?!\d))
#1
1
Well, if you want that, you can modify your regex a bit:
好吧,如果你想要,你可以修改你的正则表达式:
\B(?=(?:\d{2})*\d{3}(?!\d))
(?:\d{2})* will match even number of digits before the final \d{3}.
(?:\ d {2})*将匹配最终\ d {3}之前的偶数位数。
For PCRE engine, one that can handle integers and floating, with g enabled.
对于PCRE引擎,可以处理整数和浮动,启用g。
\G\d{1,2}\K\B(?=(?:\d{2})*\d{3}(?!\d))