i want to fetch xml file from the links like
我想从链接中获取xml文件
http://api.worldbank.org/countries/GBR/indicators/NY.GDP.MKTP.KD.ZG?date=2004:2012
it returns a xml file, i don't know how to save this file in my folder named "temp" using java or javascripts, actually i don't want to display this result of that link to the user, I'm generating such links dynamically.
它返回一个xml文件,我不知道如何使用java或javascripts将此文件保存在名为“temp”的文件夹中,实际上我不想将该链接的结果显示给用户,我正在生成这样的文件动态链接。
please help!!!
3 个解决方案
#1
10
I recommend you to use an HTML parser library like jsoup in this situation. Please have a look at the below steps for better under standing:
我建议你在这种情况下使用像jsoup这样的HTML解析器库。请查看以下步骤以获得更好的信息:
1. Download jsoup core library (jsoup-1.6.1.jar) from http://jsoup.org/download
2. Add the jsoup-1.6.1.jar file to your classpath.
3. Try the below code to save the xml file from the URL.
package com.overflow.stack;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
/**
*
* @author sarath_sivan
*/
public class XmlExtractor {
public static StringBuilder fetchXmlContent(String url) throws IOException {
StringBuilder xmlContent = new StringBuilder();
Document document = Jsoup.connect(url).get();
xmlContent.append(document.body().html());
return xmlContent;
}
public static void saveXmlFile(StringBuilder xmlContent, String saveLocation) throws IOException {
FileWriter fileWriter = new FileWriter(saveLocation);
BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);
bufferedWriter.write(xmlContent.toString());
bufferedWriter.close();
System.out.println("Downloading completed successfully..!");
}
public static void downloadXml() throws IOException {
String url = "http://api.worldbank.org/countries/GBR/indicators/NY.GDP.MKTP.KD.ZG?date=2004:2012";
String saveLocation = System.getProperty("java.io.tmpdir")+"sarath.xml";
XmlExtractor.saveXmlFile(XmlExtractor.fetchXmlContent(url), saveLocation);
}
public static void main(String[] args) throws IOException {
XmlExtractor.downloadXml();
}
}
4. Once the above code is executed successfully, a file named "sarath.xml" should be there in your temp folder.
Thank you!
#2
0
Well your body is XML not HTML, just retrieve it using Apache HttpClient, and pump the read InputStream to a FileOutputStream. What was the problem? Do you want to save parsed content in a formatted form?
那么你的身体是XML而不是HTML,只需使用Apache HttpClient检索它,并将读取的InputStream泵送到FileOutputStream。有什么问题?您想以格式化的形式保存已解析的内容吗?
#3
0
public String execute() {
try {
String url = "http://api.worldbank.org/countries/GBR/indicators/NY.GDP.MKTP.KD.ZG?date=2004:2012";
String saveLocation = System.getProperty("java.io.tmpdir")+"sarath.xml";
XmlExtractor.saveXmlFile(XmlExtractor.fetchXmlContent(url), saveLocation);
} catch (Exception e) {
e.printStackTrace();
addActionError(e.getMessage());
}
return SUCCESS;
}
#1
10
I recommend you to use an HTML parser library like jsoup in this situation. Please have a look at the below steps for better under standing:
我建议你在这种情况下使用像jsoup这样的HTML解析器库。请查看以下步骤以获得更好的信息:
1. Download jsoup core library (jsoup-1.6.1.jar) from http://jsoup.org/download
2. Add the jsoup-1.6.1.jar file to your classpath.
3. Try the below code to save the xml file from the URL.
package com.overflow.stack;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
/**
*
* @author sarath_sivan
*/
public class XmlExtractor {
public static StringBuilder fetchXmlContent(String url) throws IOException {
StringBuilder xmlContent = new StringBuilder();
Document document = Jsoup.connect(url).get();
xmlContent.append(document.body().html());
return xmlContent;
}
public static void saveXmlFile(StringBuilder xmlContent, String saveLocation) throws IOException {
FileWriter fileWriter = new FileWriter(saveLocation);
BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);
bufferedWriter.write(xmlContent.toString());
bufferedWriter.close();
System.out.println("Downloading completed successfully..!");
}
public static void downloadXml() throws IOException {
String url = "http://api.worldbank.org/countries/GBR/indicators/NY.GDP.MKTP.KD.ZG?date=2004:2012";
String saveLocation = System.getProperty("java.io.tmpdir")+"sarath.xml";
XmlExtractor.saveXmlFile(XmlExtractor.fetchXmlContent(url), saveLocation);
}
public static void main(String[] args) throws IOException {
XmlExtractor.downloadXml();
}
}
4. Once the above code is executed successfully, a file named "sarath.xml" should be there in your temp folder.
Thank you!
#2
0
Well your body is XML not HTML, just retrieve it using Apache HttpClient, and pump the read InputStream to a FileOutputStream. What was the problem? Do you want to save parsed content in a formatted form?
那么你的身体是XML而不是HTML,只需使用Apache HttpClient检索它,并将读取的InputStream泵送到FileOutputStream。有什么问题?您想以格式化的形式保存已解析的内容吗?
#3
0
public String execute() {
try {
String url = "http://api.worldbank.org/countries/GBR/indicators/NY.GDP.MKTP.KD.ZG?date=2004:2012";
String saveLocation = System.getProperty("java.io.tmpdir")+"sarath.xml";
XmlExtractor.saveXmlFile(XmlExtractor.fetchXmlContent(url), saveLocation);
} catch (Exception e) {
e.printStackTrace();
addActionError(e.getMessage());
}
return SUCCESS;
}