十进制数到字节数组的字符串[c＃]

I have problem in c# with convert decimal number from string to byte array. I want creat BigInteger with using byte array.

我在c＃中遇到问题，从字符串到字节数组的转换十进制数。我希望创建BigInteger使用字节数组。

I try:

我试试：

string Astr = "123456789123456789123456789123456789123456789123456789123456789123456789123456789";
byte[] AByte = Astr.Select(c => (byte)(c - '0')).ToArray(); //This is problem because array padding wrong.

Tnaks for your ideas. :)

Tnaks为您的想法。 :)

1 个解决方案

#1

Why do you need to create the BigInteger from a byte array when you have the string available?

当字符串可用时，为什么需要从字节数组创建BigInteger？

Why not just do this?

为什么不这样做呢？

string aStr = "123456789123456789123456789123456789123456789123456789123456789123456789123456789";
BigInteger x = BigInteger.Parse(aStr);

Also note that there is no easy correspondence between a BigInteger in string form and its byte array.

另请注意，字符串形式的BigInteger与其字节数组之间没有简单的对应关系。

For example, following on from the code above, if you add this:

例如，从上面的代码开始，如果你添加这个：

var ba = x.ToByteArray();
Console.WriteLine(string.Join(" ", ba.Select(v => v.ToString("x"))));

The output is:

输出是：

15 5f 4 84 b6 70 28 c7 73 7b a3 d5 f9 b a1 8 67 12 b0 a5 af 52 ba cb e4 66 6c 75 78 66 92 31 2a 4

Which is the byte[] version of the original string after being encoded as a BigInteger.

在编码为BigInteger之后，哪个是原始字符串的byte []版本。

#1