如何使用带数组的BigInteger ?

时间:2021-12-31 16:48:37

I'm working on altering my Fibonacci sequencer so that the numbers after reaching ~100th term don't wrap around and become negative. How do I use BigInteger in this code that I wrote:

我正在修改我的斐波那契数列,这样在~100项之后的数字就不会缠绕而变成负数。如何在我写的代码中使用BigInteger:

package me.kevinossia.mystuff;

import java.util.Scanner;

public class FibonacciDisplayer 
{
public static void main(String[] args)
{

    Scanner input = new Scanner(System.in);
    int total;
    System.out.print("This is a Fibonacci sequence displayer.\nHow many numbers would you like it to display?");
    total = input.nextInt();
    long[] series = new long[total];
    series[0]=0;
    series[1]=1;

    for(int i=2;i<total;i++)
    {
        series[i]=series[i-1] + series[i-2];
    }
    for(int j=0; j<total; j++)
    {
        System.out.print(series[j] + "\n");
    }
    input.close();
}
}

I've searched google high and low and I can't find anything specific to my case.

我搜索了谷歌的高低,我找不到任何与我的情况有关的东西。

2 个解决方案

#1


4  

If you are sure that you only want to use BigInteger then you should think of creating array of BigInteger. So like

如果您确定只想使用BigInteger,那么应该考虑创建BigInteger数组。就像

BigInteger[] series = new BigInteger[total];
series[0]=BigInteger.ZERO;
series[1]=BigInteger.ONE;

and in loop do
series[i] = series[i-1].add(series[i-2])

See this add API

看到这个API添加

#2


1  

If total is also BigInteger, then

如果total也是BigInteger,则

BigInteger total = new Biginteger("1000000000000000");
BigInteger[] series = new BigInteger[total.intValue()];
series[0]=BigInteger.ZERO;
series[1]=BigInteger.ONE;
series[i] = series[i-1].add(series[i-2])`

#1


4  

If you are sure that you only want to use BigInteger then you should think of creating array of BigInteger. So like

如果您确定只想使用BigInteger,那么应该考虑创建BigInteger数组。就像

BigInteger[] series = new BigInteger[total];
series[0]=BigInteger.ZERO;
series[1]=BigInteger.ONE;

and in loop do
series[i] = series[i-1].add(series[i-2])

See this add API

看到这个API添加

#2


1  

If total is also BigInteger, then

如果total也是BigInteger,则

BigInteger total = new Biginteger("1000000000000000");
BigInteger[] series = new BigInteger[total.intValue()];
series[0]=BigInteger.ZERO;
series[1]=BigInteger.ONE;
series[i] = series[i-1].add(series[i-2])`